A 12kg mass undergoes simple harmonic motion with an amplitude of 10cm. If the force constant for the spring is 320N/m: a) Calculate the total energy of the mass spring system. Et=½kA^2 =½(320N/m)(0.1m)^2 =1.6 J b) Calculate the maximum speed of the mass. Et=½mv^2 + ½kx^2 1.6 J = ½(12kg)v^2 + 0 v^2 = (3.2/12) = √0.2667 m/s =0.52 =5.2 x 10^-1 c) Calculate the speed of the mass when it is 5.0 cm from the equilibrium point. And this one I'm not entirely sure... do I use a= (kx) / (m) ?