Harmonic Series: Is ∑(1/ k+1 ) Divergent?

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SUMMARY

The discussion centers on the divergence of the harmonic series, specifically comparing the series ∑(1/k) and ∑(1/(k+1)). Participants confirm that both series diverge, with the latter being a shifted version of the former. The key takeaway is that the divergence of the series is due to their harmonic nature, not the other way around. The correct interpretation is that ∑(1/(k+1)) diverges similarly to ∑(1/k) when k starts from 1.

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Homework Statement


i know that k = 0 to∞∑(1/ k) is harmonic series( we know that the sum is divergent) , how about ∑(1/ k+1 ) ?

Homework Equations

The Attempt at a Solution


in my opinion , it's also harmonic series , because the sum is divergent . Am i right ?
 
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foo9008 said:

Homework Statement


i know that k = 0 to∞∑(1/ k) is harmonic series( we know that the sum is divergent) , how about ∑(1/ k+1 ) ?

Homework Equations

The Attempt at a Solution


in my opinion , it's also harmonic series , because the sum is divergent . Am i right ?

Note: the series cannot be ##\sum_{k=0}^{\infty} 1/k## because the first term would be 1/0. However, starting at ##k = 1## is OK.

Do you mean that one of the series is ##\sum_{k=1}^{\infty} 1/k## and the other is ##\sum_{k=1}^{\infty}(\frac{1}{k}+1)##? That is what you wrote. Did you really mean ##\sum_{k=1}^{\infty} 1/(k+1)## for the second series? If so, use parentheses, like this: 1/(k+1).

Anyway, just write out the first first few terms of both of your series, to see how they are related.

When you say "it's also harmonic series , because the sum is divergent" you have it backwards: it is not harmonic because it is divergent; it is divergent because it is harmonic. (Lots of divergent series are not at all harmonic.)
 
Ray Vickson said:
Note: the series cannot be ##\sum_{k=0}^{\infty} 1/k## because the first term would be 1/0. However, starting at ##k = 1## is OK.

Do you mean that one of the series is ##\sum_{k=1}^{\infty} 1/k## and the other is ##\sum_{k=1}^{\infty}(\frac{1}{k}+1)##? That is what you wrote. Did you really mean ##\sum_{k=1}^{\infty} 1/(k+1)## for the second series? If so, use parentheses, like this: 1/(k+1).

Anyway, just write out the first first few terms of both of your series, to see how they are related.

When you say "it's also harmonic series , because the sum is divergent" you have it backwards: it is not harmonic because it is divergent; it is divergent because it is harmonic. (Lots of divergent series are not at all harmonic.)
i mean second one , IMO , it is also harmonic ... , am i right ?
 
foo9008 said:
i mean second one , IMO , it is also harmonic ... , am i right ?

Have you tried to write out the first few terms of both series to see how they differ? If you do, you can answer your own question.
 
The infinite sum of 1/(k+1), with k starting from 1, is the same as the infinite sum of 1/k, with k starting from one minus 1. Follow Ray Vickson's advice to see this.
 
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