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Have manometer given density and mass

  1. Mar 27, 2012 #1
    1. The problem statement, all variables and given/known dataAssume you have a U-shaped, hollow tube (we call it a manometer) with Karo syrup (density 1200 kgm-3) in it such that both arms are half filled. What would happen if you added a given mass of water (1000 kgm-3) into one of the arms of the manometer? (the mass has less volume than half the arm of the manometer)



    2. Relevant equations



    3. The attempt at a solution F=mg=v*p*g F=(1000kgm-3)(9.8m/s2)=9800N
     
  2. jcsd
  3. Mar 27, 2012 #2

    berkeman

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    Staff: Mentor

    Welcome to the PF.

    Your work doesn't really go towards the question, IMO. You need to draw a sketch (or post the one in your textbook) of the manometer in equilibrium before and then after adding the water to one side. Your answer should reflect the difference in the heights of the two tops of liquid in the two sides of the manometer.

    Please post a sketch of the before/after situations, and then work out the difference between the two heights in the after state.
     
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