Have manometer given density and mass

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SUMMARY

The discussion centers on the behavior of a U-shaped manometer containing Karo syrup (density 1200 kg/m³) when a mass of water (density 1000 kg/m³) is added to one arm. The initial equilibrium state of the manometer must be analyzed, followed by determining the change in liquid heights after the water is introduced. The force exerted by the water is calculated using F=mg, yielding a force of 9800 N. A sketch illustrating the before and after states is essential for visualizing the height differences in the liquid columns.

PREREQUISITES
  • Understanding of fluid mechanics principles
  • Knowledge of density and its impact on fluid equilibrium
  • Ability to apply the equation F=mg in practical scenarios
  • Familiarity with manometer functionality and applications
NEXT STEPS
  • Research the principles of hydrostatic pressure in fluids
  • Learn how to calculate pressure differences in manometers
  • Study the effects of adding different fluids in a manometer setup
  • Explore the concept of buoyancy and its relation to fluid density
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Students studying fluid mechanics, physics educators, and anyone interested in understanding the principles of pressure measurement using manometers.

p.mcnamara
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Homework Statement

Assume you have a U-shaped, hollow tube (we call it a manometer) with Karo syrup (density 1200 kgm-3) in it such that both arms are half filled. What would happen if you added a given mass of water (1000 kgm-3) into one of the arms of the manometer? (the mass has less volume than half the arm of the manometer)



Homework Equations





The Attempt at a Solution

F=mg=v*p*g F=(1000kgm-3)(9.8m/s2)=9800N
 
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p.mcnamara said:

Homework Statement

Assume you have a U-shaped, hollow tube (we call it a manometer) with Karo syrup (density 1200 kgm-3) in it such that both arms are half filled. What would happen if you added a given mass of water (1000 kgm-3) into one of the arms of the manometer? (the mass has less volume than half the arm of the manometer)



Homework Equations





The Attempt at a Solution

F=mg=v*p*g F=(1000kgm-3)(9.8m/s2)=9800N

Welcome to the PF.

Your work doesn't really go towards the question, IMO. You need to draw a sketch (or post the one in your textbook) of the manometer in equilibrium before and then after adding the water to one side. Your answer should reflect the difference in the heights of the two tops of liquid in the two sides of the manometer.

Please post a sketch of the before/after situations, and then work out the difference between the two heights in the after state.
 

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