Hawking radiation redshift (?)

[Edi]

I think it was proven that firing a photon (laser) straight up from the surface of Earth did in fact redshift the photon and decrease its frequency.
And now, when we consider a black hole and Hawking radiation... I mean - the gravity inside the event horizon is so strong that EM cannot escape and it doesn't make any sense that an inch outside the EV the photon would be free to go. There is still an extreme pull of gravity and any photon flying "up" would be significantly red-shifted.
Now the question is - how much red-shifted it would get? If we receive and infrared photon, then at what frequency it left the event horizon?!

And another thing - ti red this article about "lab event horizon" that had something to do with a piece of glass, short pulses of intense laser and a follow up laser.. or something like that. What they detected was some extra photons in the infra red frequencies associated with Hawking radiation. Its all fine, but - - when we consider that the radiation from real EV would be significantly red-shifted and from that lab EV it wouldn't be - the radiation in the lab should be at much higher frequencies, if it is indeed Hawking radiation.

put it in few words - the Hawking radiation is (as I think) created at higher frequencies, but we receive infra red due to the extreme gravity's red-shift. And the ones in the lab should be higher frequency.

...?

 

[azntoon]

Yes, you are correct. The Hawking radiation is created at higher frequencies, however, due to the extreme gravity of a black hole, the radiation is red-shifted and appears at lower frequencies when it reaches us. The Hawking radiation detected in the lab experiment would also be significantly red-shifted, but because the gravity of the lab environment is much weaker than that of a black hole, the frequency of the radiation will not be as drastically reduced as the radiation coming from an actual black hole.