Heat Engine Cycles: Understanding Reversible Changes

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SUMMARY

The discussion focuses on the analysis of reversible heat engine cycles as described in Adkins' "Introduction to Thermal Physics." Participants derive the relationship between infinitesimal temperature changes of two bodies, leading to the equation 0 = C1 dT1/T1 + C2 dT2/T2. The final equilibrium temperature Tf is established as TfC1 + C2 = T1C1 T2C2. Additionally, the impact of irreversibility on Tf is explored, suggesting that Tf could be approximated as the average of T1 and T2.

PREREQUISITES
  • Understanding of thermodynamic concepts, specifically heat engines.
  • Familiarity with the first law of thermodynamics (U = Q + W).
  • Knowledge of calculus, particularly integration and differential equations.
  • Basic principles of entropy and reversible processes.
NEXT STEPS
  • Study the derivation of the Carnot cycle and its implications for efficiency.
  • Explore the concept of entropy in irreversible processes.
  • Learn about the mathematical treatment of thermodynamic cycles using differential equations.
  • Investigate real-world applications of reversible and irreversible heat engines.
USEFUL FOR

Students of thermodynamics, physics educators, and engineers interested in heat engine design and efficiency optimization.

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Homework Statement


Taken from adkins Introduction to thermal physics

A reversible heat engine is operated between two bodies, one
of heat capacity C1 initially at temperature T1 and the other of
heat capacity C2 initially at temperature T2. As the engine
operates, the warmer body gradually cools and the cooler one
is warmed.
(a) By considering the changes that occur in one cycle of the
engine, show that infinitesimal changes of temperature of the
two bodies are related by

0 = C1 dT1/T1 + C2 dT2/T2

Eventually, the bodies reach the same temperature Tf and
the heat engine ceases to run. Show that Tf is given by

TfC1 + C2 = T1C1 T2C2

Homework Equations



U = Q + W

The Attempt at a Solution



For the first part

I am taking the U to be 0 and W = 0 ... This probably is not be correct.

0 = C1 (T1 + dt) + C2(T2-dt)... this does lead me to the correct solution.

Any hints would be greatly appreciated!
 
Last edited:
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Alright I figured out this question ...

Its a simple manipulation of the dQ = T ds equation for each Temperature. Then you can equate them by using S1 = -S2 and finally integrate.

The last part of this question ask what the Tf would be if the process was irreversible. I think this would just be the average:

Tf = (T1 + T2)/2

however I have a feeling I am missing something. Any suggestions would be great!
 
Last edited:

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