2 body engine, final equilibrium temperate and work produced

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1. Jul 18, 2017

mrmerchant786

1. The problem statement, all variables and given/known data
2 bodies with contant heat capacity C and 2C, are initially at temp T and 2T. if a heat engine executing a reversible carnot cycle operates between the two bodies until their temperatures are equal, what is the final temp of the bodies and how much work is preformed by the heat engine

2. Relevant equations
W=Qη dQ=CdT

3. The attempt at a solution
q2 = C2 * (Tf-T2)
q1 = C1 * (Tf-T1)
So far this is where I'm at, I don't know how to proceed further to find the equilibrium temperature and then to fine the work produced

2. Jul 18, 2017

Staff: Mentor

Suppose T* is the final temperature. In terms of T*, what is the change in entropy of each of the two reservoirs. Since you are operating using a Carnot cycle, the change in entropy of the working fluid is equal to zero. What does that tell you about the total of the entropy changes of the two reservoirs?

3. Jul 19, 2017

mrmerchant786

will it be zero?
so s1 +s2 = 0

4. Jul 19, 2017

Staff: Mentor

Yes. $\Delta S_1+\Delta S_2=0$

5. Jul 19, 2017

Staff: Mentor

So, have you solved it yet?