Understanding Heat of Atomization: Equations and Problem-Solving Techniques

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SUMMARY

The discussion focuses on the heat of atomization, specifically the equations for atomizing graphite and methane (CH4). The correct equation for the atomization of graphite is C(graphite) → C(gas), while the heat of atomization for CH4 is 1660 kJ/mol. Participants clarify that the equations must accurately reflect the gaseous state of CH4 and that the heat values for atomization should be adjusted based on the stoichiometry of the reactions. The final consensus emphasizes the importance of correctly interpreting the definitions provided in textbooks.

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  • Knowledge of heat of atomization values for common substances
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Lori

Homework Statement


So, my textbook doesn't go over these type of problems for heat of atomization , so I am confused on how to write the chemical equations for them.

Question: The heat of atomization is the heat needed to separated gaseous atoms from a substance in its standard state. The equation for the atomization of graphite is C(graphite) --> C(gas)

Homework Equations


Given,
1) Heat of formation for CH4 = -74.9 Kj/mol
2)Heat of atomization for CH4 = 1660 kj/mol
3) heat of atomization for H2 = 423 kj/mol

The Attempt at a Solution


For the equation number 1, i got C(graphite) + 2H2 -> CH4(s)
for number 2, i got C(graphite) + 4H -> C(g) + H(g)
For 3, i got 1/2H2(g) --> H(g)

I'm not sure if the second one is write. I was thinking that if i was able to write the equations correctly, then i can do some cancellation so i get C(graphite) --> C(gas).
 
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CH4 is not solid (check your first equation). In the second you should have just CH4(g) on the left, not some combination of separated elements.
 
Borek said:
CH4 is not solid (check your first equation). In the second you should have just CH4(g) on the left, not some combination of separated elements.
Borek said:
CH4 is not solid (check your first equation). In the second you should have just CH4(g) on the left, not some combination of separated elements.
So it should look like this?

C(graphite) + 2H2(g) -> CH4(g)
CH4(g) -> C(g) + H(g)
1/2H2(g) --> H(g)

How would the kj/mol change for each equation? Would they remain the same?
 
First two equations look OK, I think the last one should be doubled - it is about atomizing a molecule, not half of the molecule. But in general you should check what definition you were given, as these things are often ambiguous.
 

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