Heat transfer by radiation between two plates

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SUMMARY

The discussion focuses on calculating the energy transfer rate between two parallel plates in a vacuum, held at temperatures of 2000K and 3000K, using the Stefan-Boltzmann Law. The energy emission rate per unit area is determined to be 368 W/m², assuming black body conditions. The conversation highlights the significance of emissivity, clarifying that while it affects the magnitude of energy flow, it does not alter the direction of heat transfer, which always flows from the hotter to the cooler body. The participants emphasize that emissivity must be considered in practical scenarios, even if the problem assumes ideal black bodies.

PREREQUISITES
  • Understanding of the Stefan-Boltzmann Law
  • Knowledge of thermal radiation principles
  • Familiarity with concepts of emissivity and black body radiation
  • Basic thermodynamics and heat transfer concepts
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  • Explore advanced applications of the Stefan-Boltzmann Law in engineering
  • Learn about the role of thermal radiation in vacuum environments
  • Investigate the effects of surface properties on energy exchange rates
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Students and professionals in physics, mechanical engineering, and thermal sciences who are interested in understanding heat transfer mechanisms and the role of emissivity in radiation processes.

Karol
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Homework Statement


Two large plates are parallel and close to each other, vacuum is between them. they are held at 2000K and 3000K.
What is the energy transfer rate between them.

Homework Equations


The energy emission rate per unit area-the Stefan-Boltzmann Law: $$R=\varepsilon\sigma T^4$$
##\varepsilon## is the emissivity of the surface
##\sigma=5.672E-8[w/sec]##

The Attempt at a Solution


The solution is 368[w/m2], it's the answer if the emission is of a black body:
##1\cdot 5.672E-8\cdot\left(300^4-200^4\right)=368##
But why don't the emissivities of the surfaces count? what if one surface emits more or less than the other?
In the Stefan-Boltzmann formula the outer temperature exists, not the nature of the surrounding surfaces.
I guess it has something to do with the fact that the rest of the radiation, which isn't absorbed, is reflected and comes into account
 
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Karol said:
But why don't the emissivities of the surfaces count?
They do count, and the problem statement should specify that ideal black bodies are meant. The sign of the energy transfer cannot change, but the overall magnitude of exchanged energy can go down.
 
mfb said:
The sign of the energy transfer cannot change, but the overall magnitude of exchanged energy can go down.
What do you mean by "sign"?
 
Karol said:
What do you mean by "sign"?
Meaning which way the net flow goes.
If one body has lower emissivity than that of a black body then it both emits less and absorbs less. Different emissivities cannot result in the net flow being from the cooler to the hotter.
 
Of course not from the cooler to the hotter, but different emissivities must mean smaller energy flow. it doesn't matter which plate's emissivity is smaller, right?
 
Karol said:
Of course not from the cooler to the hotter
You say 'of course', but if the emissivity affected only the emission rate and not the absorption rate then you could have the paradoxical situation that a hot body with low emissivity could gain energy from a cooler body.
but different emissivities must mean smaller energy flow. it doesn't matter which plate's emissivity is smaller, right?
It's not that they're different, just that one, the other or both are lower than a black body's.
 
Thanks
 
Why in an insulated chamber the emission of a body and the emission of the walls is black body? why don't we take into account the emissivity of the walls?
 
Karol said:
Why in an insulated chamber the emission of a body and the emission of the walls is black body?
It is not.
The energy density in the cavity does not depend on the emissivity, but the energy exchange rate with the objects does.
 
  • #10
mfb said:
The energy density in the cavity does not depend on the emissivity
Why? if the walls inside emit low radiation, because of small emissivity, then the energy density in the opening will also be low, no?
 
  • #11
Karol said:
Why? if the walls inside emit low radiation, because of small emissivity, then the energy density in the opening will also be low, no?
No. This is exactly the same point as for the two bodies at different temperatures. If the emissivity is low then the absorption from the cavity is correspondingly low. Equilibrium will still be achieved when the energy density corresponds to the temperature of the enclosure.
 

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