1. The problem statement, all variables and given/known data An ideal liquid flows horizontally through a pipe of cross sectional area 3cm2 with a velocity 1ms-1. The pipe narrows to a cross sectional area 1cm2. 2 vertical pipes are connected to the pipe, one in either region. Calculate the height difference of the liquid between the 2 vertical pipes. 2. Relevant equations p1 + 0.5ρv12 + ρgh1 = p2 + 0.5ρv22 + ρgh2 A1v1 = A2v2 3. The attempt at a solution I think i'm a bit confused on what my variables represent in bernoullis equation: Using the continuity equation gives v2 = 3ms-1. Then I said that for the pipes p1 = p2 (because they're both open to the atmosphere), putting everything into bernoullis equation and rearranging gives h1 - h2 = 0.4 m The book says the answer is 4x10-3 m. Am I not allowed to consider the heights of the fluid in the vertical pipe because I calculated the speeds of the fluid in the horizontal pipe? I can't think of any other way to do the problem.