Helicopter tail rotor thrust requirement

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SUMMARY

The calculation of thrust required by a helicopter's tail rotor to counteract the main rotor's torque is determined using the horsepower and RPM of the main rotor. For a model helicopter with 0.05 horsepower (37 watts) and a rotor speed of 300 RPM, the torque is calculated as 0.88 ft-lb. Consequently, the thrust required for the tail rotor at a tail boom length of 3.5 feet is 0.25 lbs. The formula used for torque calculation is T = 63025 * hp / rpm for in-lbs and T = 5252 * hp / rpm for ft-lbs.

PREREQUISITES
  • Understanding of helicopter mechanics
  • Knowledge of torque calculations
  • Familiarity with horsepower and RPM concepts
  • Basic principles of moment balance
NEXT STEPS
  • Research the impact of tail boom length on tail rotor thrust requirements
  • Learn about torque calculations in different units (in-lbs vs. ft-lbs)
  • Explore the relationship between horsepower, RPM, and thrust in helicopter design
  • Investigate advanced helicopter dynamics and stability control mechanisms
USEFUL FOR

Aerospace engineers, helicopter designers, model helicopter enthusiasts, and students studying rotorcraft dynamics will benefit from this discussion.

PaulHP
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How can you calculate the amount of thrust needed by the tail rotor of a helicopter to counter the torque of the main rotor?
 
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Welcome to PF.

The answer to the question depends on what you know. If you know the horsepower and rpm of the main rotor, you can calculate the torque easily enough. More information is needed before we can help you...
 
lets say that this is for a model helicopter with .05 hp (37 watts), has blades that rotate at 300 rpm and has a 3.5 foot long tail boom. Wouldn't the required thrust of the tail rotor be cut in half if the tail boom length is doubled?
 
Making the tail boom longer would decrease the power requirements of the tail rotor.
 
Thanks, I thought it would, but how would you determine exactly how much thrust would be needed for the tail rotor at various tail boom lengths?
 
Just do a moment balance.
 
Well, you have the horsepower and rpm. Torque is horsepower/rpm...
 
ah. So, 0.88 ft-lb would be required to counter balance to main rotor and the thrust required for the tail rotor at 3.5 feet would be 0.25 lbs, right?
 
I can tell you yes or no if you show some steps as to how you got to your final answer.
 
  • #10
0.05 hp X 5252= 262.6/300 rpm = 0.88 ft-lb
0.88/3.5 ft= 0.25 lbs of thrust
 
  • #11
T = 63025*hp/rpm

this "0.05 hp X 5252= 262.6/300 rpm = 0.88 ft-lb" Makes no sense to me.

I get 3lbs of thrust.
 
  • #12
Cyrus said:
T = 63025*hp/rpm

this "0.05 hp X 5252= 262.6/300 rpm = 0.88 ft-lb" Makes no sense to me.

I get 3lbs of thrust.

T = 63025*hp/rpm is to find torque in in-lbs, and T-5252*hp/rpm is to find it in ft-lbs..
 
  • #13
PaulHP said:
T = 63025*hp/rpm is to find torque in in-lbs, and T-5252*hp/rpm is to find it in ft-lbs..

Yep you're right :-p
 

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