PaulHP
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How can you calculate the amount of thrust needed by the tail rotor of a helicopter to counter the torque of the main rotor?
The calculation of thrust required by a helicopter's tail rotor to counteract the main rotor's torque is determined using the horsepower and RPM of the main rotor. For a model helicopter with 0.05 horsepower (37 watts) and a rotor speed of 300 RPM, the torque is calculated as 0.88 ft-lb. Consequently, the thrust required for the tail rotor at a tail boom length of 3.5 feet is 0.25 lbs. The formula used for torque calculation is T = 63025 * hp / rpm for in-lbs and T = 5252 * hp / rpm for ft-lbs.
PREREQUISITESAerospace engineers, helicopter designers, model helicopter enthusiasts, and students studying rotorcraft dynamics will benefit from this discussion.
Cyrus said:T = 63025*hp/rpm
this "0.05 hp X 5252= 262.6/300 rpm = 0.88 ft-lb" Makes no sense to me.
I get 3lbs of thrust.
PaulHP said:T = 63025*hp/rpm is to find torque in in-lbs, and T-5252*hp/rpm is to find it in ft-lbs..