Help a Struggling Maths Student Solve a Quadratic Equation

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SUMMARY

The discussion centers on solving the quadratic equation k^2 + (k + 4)^2 = 346. The correct expansion of (k + 4)^2 using the FOIL method results in k^2 + 8k + 16, clarifying the origin of the 8k term. The final solution to the equation is k = 11. Participants emphasize the importance of correctly applying polynomial multiplication rather than simplifying incorrectly.

PREREQUISITES
  • Understanding of quadratic equations
  • Familiarity with polynomial expansion techniques
  • Knowledge of the FOIL method for binomials
  • Basic algebra skills
NEXT STEPS
  • Study polynomial multiplication techniques
  • Practice solving quadratic equations using the quadratic formula
  • Learn about the properties of quadratic functions
  • Explore graphing quadratic equations to visualize solutions
USEFUL FOR

Students struggling with algebra, particularly those in middle or high school, as well as educators seeking to reinforce concepts of polynomial expansion and quadratic equations.

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I might not be the brightest bob in the bunch but I am having trouble with a simple quadratic equation.

k^2 + (k + 4)^2 = 346

According to my manual expands to:

k^2 + k^2 + 8k + 16 = 346

Everything is going fine until I see the 8k. Where did the 8k come from? Or is my manual wrong?

If anyone is willing to aid a poor soul with his maths I would be very grateful.
 
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Hmm...

k^2 + (k+4)^2 = 346

When you square k+4, please remember that it is not k^2 + 16, but rather (k+4)(k+4), which is a polynomial. After you finish using the FOIL method, you get k^2 + 4k + 4k + 16, which can be simplified to k^2 + 8k + 16, which is how you get your 8k.

The solution to the problem is 11 :smile: (Quadratic Equation).

Besides... are you in 9th grade?
 
yes

Because (k + 4) ^2 = (k+4)(k+4) and you can't just multiply k*k and add it to 4*4 you have to multiply each element as in: k*k + k*4 + k*4 +4*4 which will give you k^2 + 8k + 16. so if you had (k+ 3)(k + 2) = k^2 + 2*k + 3*k + 6
 

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