Help calulating the monent of inertia

  • Thread starter Thread starter parttime
  • Start date Start date
  • Tags Tags
    Inertia
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 3K views
parttime
Messages
13
Reaction score
0
attachment.php?attachmentid=7049&d=1149234489.gif
three identical thin rods each of length L and massM are welded perpendicluar to one another determine the monemt of inertia of the structure pink line is the axis of rotation. i think i need to use Icm= 1/12 ML^2 and I=1/3ML^2
but not sure which rod uses which formula
 

Attachments

  • moment_of_inertia.GIF
    moment_of_inertia.GIF
    1.5 KB · Views: 554
Last edited:
Physics news on Phys.org
If the pink line is passing through the end of C then the MI for Rod C is 1/3ML^2.

For MI of A, think of the distance of different particles of the rod A from the axis.

For MI of B you have to use Parallel axis theorem. Go through it.

MP
 
thanks i got it now