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The discussion focuses on constructing a sixth-degree polynomial with specific factors: (x - 1), (x + 1), and (x - 2), including repeated linear factors and a quadratic factor without real roots. Multiple valid polynomial forms exist, such as (x - 1)4(x - 2)(x + 1) or (x - 1)2(x - 2)2(x + 1)2, where the sum of the exponents equals six. Additionally, any non-zero constant can multiply the product of these factors, allowing for further variations.

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Tstuvshu
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Need help please
 

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Any product of (x - 1), (x + 1), (x - 2) and a constant, with some repeated linear factors, quadratic factor without any real roots, or irreducible cubic factor that has 1, -1 or 2 as its roots.
 
What kind of "help" do want? For one thing, there is no single answer. There are many polynomials that satisfy these conditions! The only factors must be (x- 1), (x+ 1), and (x- 2) but that is only three and for a sixth degree polynomial you need six so some factors must be repeated. That could be $(x- 1)^4(x- 2)(x+ 1)$ or $(x-1)^2(x- 2)^2(x+ 1)^2$ or any combination of exponents that add to six. Also, the product of factors can be multiplied by any non-zero constant.
 

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