HELP how to prove (1-x^2)^n >= 1-nx^2 when x belongs to the interval [-1,1]?

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Discussion Overview

The discussion revolves around proving the inequality (1-x^2)^n ≥ 1-nx^2 for x in the interval [-1,1]. The context includes theoretical exploration and potential applications of mathematical inequalities, particularly in relation to the Stone-Weierstrass theorem.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested, Mathematical reasoning

Main Points Raised

  • One participant notes that while the inequality seems correct for larger values of n, they seek a rigorous proof applicable for all n, possibly using the binomial theorem.
  • Another participant suggests looking up Bernoulli's inequality as a relevant concept.
  • A further suggestion is made to use mathematical induction to prove the inequality.
  • Bernoulli's inequality is mentioned, which states that (1+x)^n ≥ 1+nx for x ≥ -1 and n ≥ 1, indicating a potential connection to the original inequality.

Areas of Agreement / Disagreement

Participants do not reach a consensus on a specific proof method, and multiple approaches are proposed without agreement on which is most suitable.

Contextual Notes

There may be limitations related to the assumptions required for the application of Bernoulli's inequality and the conditions under which induction could be applied. The discussion does not resolve these aspects.

Who May Find This Useful

Readers interested in mathematical inequalities, proof techniques, or the Stone-Weierstrass theorem may find this discussion relevant.

manuel huant
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i got this question when i read the proof of stone-weierstrass theorem in baby rudin , page 159 , this inequality seems right when n becomes larger, since 1-nx^2 would be negative and (1-x^2)^n always positive, but i don't know how to proved it rigorously using binomial theorem for all n , or is there any other rigorous proof ?
 
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look up Bernoulli's inequality
 
many thanks for your help~
 

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