Help: If A[itex]\subseteq[/itex]B proof C-B[itex]\subseteq[/itex]C-A

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SUMMARY

The discussion centers on proving the set inclusion C - B ⊆ C - A given that A ⊆ B. The proof utilizes logical reasoning and set theory concepts, including element-wise proof, contraposition, and definitions of set complements. Key steps include demonstrating that if an element is in C - B, it must also be in C - A, confirming the inclusion relationship. The final conclusion is that the proof is valid and correctly follows from the initial hypothesis.

PREREQUISITES
  • Understanding of set theory, specifically set inclusion and set difference.
  • Familiarity with logical reasoning and proof techniques, including contraposition.
  • Knowledge of definitions related to set complements.
  • Basic skills in mathematical notation and manipulation.
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  • Study the principles of set theory, focusing on set operations and properties.
  • Learn about proof techniques in mathematics, particularly contraposition and direct proofs.
  • Explore the definitions and applications of set complements in various mathematical contexts.
  • Practice solving problems involving set inclusions and differences to reinforce understanding.
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Students studying set theory, mathematicians working on proofs, and educators teaching mathematical logic and set operations.

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Homework Statement


Hello, I'm having problems with the following exercise from my homework.

Proof that when A[itex]\subseteq[/itex]B, then it happens that C-B[itex]\subseteq[/itex]C-A


Homework Equations





The Attempt at a Solution


This is how I have been trying to solve it:
1. A[itex]\subseteq[/itex]B // Hyp
2. x[itex]\in[/itex]A[itex]\rightarrow[/itex]x[itex]\in[/itex]B //Element wise proof [1]
3. x[itex]\in[/itex]A [itex]\wedge[/itex] x[itex]\in[/itex]B // which rule allow me to do this? [2]
4. ( x[itex]\in[/itex]A [itex]\wedge[/itex] x[itex]\in[/itex]B) [itex]\vee[/itex] x[itex]\in[/itex]C // Addition [3]
5. (x[itex]\in[/itex]A[itex]\vee[/itex]x[itex]\in[/itex]C)[itex]\wedge[/itex](x[itex]\in[/itex]B[itex]\vee[/itex]x[itex]\in[/itex]C) // Distrivutive law [4]
6. x[itex]\in[/itex]A[itex]\vee[/itex]x[itex]\in[/itex]C // [itex]\wedge[/itex] OUT [5]
7. x[itex]\in[/itex]B[itex]\vee[/itex]x[itex]\in[/itex]C // [itex]\wedge[/itex] OUT [5]
8. y[itex]\in[/itex]C // Hyp (This step is the very confusing one. I'm assuming it exists an element of one set I have no information it actually exists)
9. y[itex]\notin[/itex]B // Modus Ponendo Tollens [7,8]
10. y[itex]\in[/itex]C[itex]\wedge[/itex]y[itex]\notin[/itex]B // [itex]\wedge[/itex] IN [8,9]
11. y[itex]\notin[/itex]A // Modus Ponendo Tollens [6,8]
12. y[itex]\in[/itex]C[itex]\wedge[/itex]y[itex]\notin[/itex]A // [itex]\wedge[/itex] IN [8,11]
13. y[itex]\in[/itex]C[itex]\wedge[/itex]y[itex]\notin[/itex]B [itex]\rightarrow[/itex] y[itex]\in[/itex]C[itex]\wedge[/itex]y[itex]\notin[/itex]A // CP [10, 12]
14. C-B [itex]\subseteq[/itex] C-A // Defs of Difference [13] & Element wise proof

Sorry for my poor english. Thanks in advance for your help.
 
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ozarga said:

Homework Statement


Hello, I'm having problems with the following exercise from my homework.

Proof that when A[itex]\subseteq[/itex]B, then it happens that C-B[itex]\subseteq[/itex]C-A

Homework Equations



The Attempt at a Solution


This is how I have been trying to solve it:
1. A[itex]\subseteq[/itex]B // Hyp
2. x[itex]\in[/itex]A[itex]\rightarrow[/itex]x[itex]\in[/itex]B //Element wise proof [1]
3. x[itex]\in[/itex]A [itex]\wedge[/itex] x[itex]\in[/itex]B // which rule allow me to do this? [2]
4. ( x[itex]\in[/itex]A [itex]\wedge[/itex] x[itex]\in[/itex]B) [itex]\vee[/itex] x[itex]\in[/itex]C // Addition [3]
5. (x[itex]\in[/itex]A[itex]\vee[/itex]x[itex]\in[/itex]C)[itex]\wedge[/itex](x[itex]\in[/itex]B[itex]\vee[/itex]x[itex]\in[/itex]C) // Distrivutive law [4]
6. x[itex]\in[/itex]A[itex]\vee[/itex]x[itex]\in[/itex]C // [itex]\wedge[/itex] OUT [5]
7. x[itex]\in[/itex]B[itex]\vee[/itex]x[itex]\in[/itex]C // [itex]\wedge[/itex] OUT [5]
8. y[itex]\in[/itex]C // Hyp (This step is the very confusing one. I'm assuming it exists an element of one set I have no information it actually exists)
9. y[itex]\notin[/itex]B // Modus Ponendo Tollens [7,8]
10. y[itex]\in[/itex]C[itex]\wedge[/itex]y[itex]\notin[/itex]B // [itex]\wedge[/itex] IN [8,9]
11. y[itex]\notin[/itex]A // Modus Ponendo Tollens [6,8]
12. y[itex]\in[/itex]C[itex]\wedge[/itex]y[itex]\notin[/itex]A // [itex]\wedge[/itex] IN [8,11]
13. y[itex]\in[/itex]C[itex]\wedge[/itex]y[itex]\notin[/itex]B [itex]\rightarrow[/itex] y[itex]\in[/itex]C[itex]\wedge[/itex]y[itex]\notin[/itex]A // CP [10, 12]
14. C-B [itex]\subseteq[/itex] C-A // Defs of Difference [13] & Element wise proof

Sorry for my poor english. Thanks in advance for your help.
Generally, to prove that [itex]C-B\subseteq C-A\,,[/itex] you take an element of set C-B and show that it is an element of set C-A .
 
Thank you SammyS.

I think I figured out:

1. A[itex]\subseteq[/itex]B // hyp
2. x[itex]\in[/itex]A [itex]\rightarrow[/itex] x[itex]\in[/itex]B // for element proof
3. x[itex]\notin[/itex]B [itex]\rightarrow[/itex] x[itex]\notin[/itex]A // Contraposition
4. x[itex]\in[/itex]Bc[itex]\rightarrow[/itex]x[itex]\in[/itex]Ac // Definition of Set Complement in 3
5. x[itex]\in[/itex]C-B[itex]\rightarrow[/itex]x[itex]\in[/itex]C-A // Definition of Complement in 4
6. C-B[itex]\subseteq[/itex]C-A

Is it right?
 

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