Finding Time t for Instantaneous & Average Velocity: Particle Motion

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To find the time at which instantaneous velocity equals average velocity for the particle described by the position function s(t) = 3t² - 3t + 5 cm, first calculate the average velocity over the 10-second trip using the formula (s(10) - s(0)) / 10. The average velocity is determined by evaluating the position function at t=0 and t=10. Next, find the instantaneous velocity by taking the derivative of the position function, s'(t). Set the average velocity equal to the instantaneous velocity and solve for the time t. This approach effectively identifies the specific moment when both velocities coincide.
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The position of a particle moving in a straight line during a 10–second trip is s(t) = 3t2 − 3t + 5 cm.Find a time t at which the instantaneous velocity is equal to the average velocity for the entire trip.
 
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Average velocity = (x2 - x1)/Δt

How do you find instantaneous velocity?
 
the derivative
 
what does x represent?
 
The position. x2 - x1 is the change in position. Your object starts at one point, and ten seconds later, it's somewhere else. That somewhere else is x2.
 
sammiyahc0 said:
what does x represent?
Your "s". The average speed, between t= 0 and t=10, is (s(10)- s(0))/(10 - 0). Calculate that, set it equal to s'(t) and solve for t.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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