Help me calculate drag on objects in water

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To calculate the drag on different missile or torpedo shapes in water, the drag force can be determined using the formula: drag force = 0.5 * density of water * velocity squared * cross-sectional area * drag coefficient. Each shape's drag coefficient can be found through research, and the frontal drag is typically the dominant factor in low-speed scenarios. However, it is important to also account for the drag from the fuselage, which involves considering its length and shape for accurate calculations. The total drag can be estimated by combining the frontal drag with the laminar resistance from the fuselage. Understanding these components will help in accurately assessing the overall drag for each design.
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Homework Statement



How can I calculate the drag of different missile/torpedo shapes in water? I have five different shapes, similar cylinders with different "noses" One is a long cylinder with a flat nose, another is a cylinder of the same diameter with a hemisphere nose. Third and fourth are short and long cone-shaped noses, and the fifth is a large hemisphere (twice the diameter of the cylinder, sort of a mushroom shape). They all have identical surface area (were designed that way) and are powered by identical electric motors. But they move through water at different speeds, presumably because of their different shapes or "streamlining."

We're talking about low speeds here, these are models of approx. 14-18 inches long propelled by a small 3 volt electric motor.

Is there a formula for calculating the drag or drag coefficient of these different shapes? Is there a rule of thumb (I have heard 90 %) for the amount of drag caused by the torpedos' frontal area/cross section vs. the amount of drag caused by laminar/surface friction?

Thanks, any help is appreciated!



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The Attempt at a Solution

 
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You can use the formula here, however I am unsure as to the exact values for the drag coefficients of your shapes.
 
The link you pasted is not active, but I bet you're suggesting the formula for drag, i.e. the force of drag = one-half the density of the medium, times the velocity squared, times the cross-sectional area of the object, times the drag coefficient for that shape. If correct, I've done some searching and found drag coefficients for all my "shapes" of torpedo. Actually, it's the torpedo "noses"...flat cylinder, hemisphere, long cone, short cone.

So I can basically calculate that, and as I understand it the "frontal" drag is the main drag effect.

However each torpedo has a body too, a fuselage if you will...so how do I calculate the drag on that, the "laminar" resistance or whatever, and add it to the frontal drag for a total?

I've found lots of examples for calculating the frontal drag of different-shaped objects, but the length and shape (pure cylinder, gentle taper, rounded, etc.) of the fuselage/body must matter too...how to measure drag there?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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