Finding an Indeterminate Limit with L'Hôpital's Rule: Help and Explanation

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The discussion focuses on finding the limit of the expression lim x → ∞ ( x rx ) for r < 1, which is an indeterminate form of ∞ * 0. Participants clarify that L'Hôpital's Rule can be applied to both 0/0 and ∞/∞ forms. A suggested approach is to rewrite the limit as lim x → ∞ (x/(1/r)x), which allows for the correct application of L'Hôpital's Rule to resolve the indeterminate form.

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swampwiz
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I can't seem to figure out how to find this seemingly simple limit (that is shown numerically to go to 0)

lim x → ∞ ( x rx )

for r < 1

This is an indeterminate form of ∞ * 0, but when I try to apply L'Hôpital's rule as

lim x → ∞ ( rx / ( 1 / x ) )

I end up getting an expression of the form x2 rx, with further application of the rule generating higher and higher powers of x

I'm totally stuck!
 
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You have the right idea. Try this instead:

lim x → ∞ (x/(1/r)x)
 
gb7nash said:
You have the right idea. Try this instead:

lim x → ∞ (x/(1/r)x)

But wouldn't that be ∞ / ∞ ? L'Hopital's rule only applies to 0 / 0
 
swampwiz said:
L'Hopital's rule only applies to 0 / 0

No it doesn't. It also applies to +- inf/inf
 
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