MHB Help Me Solve $\text{Im}(z^3)$ in Rectangular Form

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To find the imaginary part of \( z^3 \) in rectangular form, where \( z = x + jy \), the expression simplifies to \( \text{Im}(x^3 + 3x^2jy - 3xy^2 - jy^3) \). The relevant terms containing \( j \) are \( 3x^2jy - jy^3 \), leading to \( \text{Im}((x^3 - 3xy^2) + (3x^2y - y^3)j) \). The imaginary part is identified as \( 3x^2y - y^3 \). Thus, the final answer for \( \text{Im}(z^3) \) is \( 3x^2y - y^3 \).
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I don't how to proceed further

Let $z=x+jy$ find in rectangular form:

1. $\text{Im}(z^3)$

this is where I can get to,

$\text{Im}(x^3+3x^2jy+3xj^2y^2+j^3y^3)=\text{Im}(x^3+3x^2jy-3xy^2-jy^3)$

please help me.
 
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Drain Brain said:
I don't how to proceed further

Let $z=x+jy$ find in rectangular form:

1. $\text{Im}(z^3)$

this is where I can get to,

$\text{Im}(x^3+3x^2jy+3xj^2y^2+j^3y^3)=\text{Im}(x^3+3x^2jy-3xy^2-jy^3)$

please help me.

So what are the terms which have a "j" part?
 
Drain Brain said:
I don't how to proceed further

Let $z=x+jy$ find in rectangular form:

1. $\text{Im}(z^3)$

this is where I can get to,

$\text{Im}(x^3+3x^2jy+3xj^2y^2+j^3y^3)=\text{Im}(x^3+3x^2jy-3xy^2-jy^3)$

please help me.

Hi Drain Brain! :)

You're already there:
$$\text{Im}(x^3+3x^2jy-3xy^2-jy^3) = \text{Im}((x^3-3xy^2)+(3x^2y-y^3)j)
= (3x^2y-y^3)$$
 
they are $3x^2yj-j^3$ is this the answer?
 
Drain Brain said:
they are $3x^2yj-j^3$ is this the answer?

no .as I like serena mentioned it is
$3x^2y- y^3$ because imaginary part of $x+jy$ is $y $
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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