Help Needed: Calculating Mass/Charge Ratio & Carbon Atom Count

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SUMMARY

The discussion focuses on calculating the mass-to-charge ratio of toner particles in a photocopier, where the electric field near the imaging drum is 1.40 x 10^5 N/C. It is established that the force attracting the toner particle must be ten times its weight. The mass-to-charge ratio cannot be determined without additional data. However, it is confirmed that each excess electron on a toner particle corresponds to approximately 6 x 10^23 carbon atoms, indicating the particle's composition.

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  • Understanding of electric fields and forces in physics
  • Knowledge of mass-to-charge ratio calculations
  • Familiarity with the structure of carbon and atomic quantities
  • Basic principles of photocopier operation and toner composition
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Students and professionals in physics, materials science, and engineering, particularly those interested in the principles of electrostatics and photocopier technology.

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Hi I am just having trouble figuring out this question. If someone can help me out it would be greatly appreciated

The imaging drum of a photocopier is positively charged to attract negatively charged particles. Near the surface of the drum, its electric field has a magnitude of 1.40 * 10^5 N/C. A toner particle is to be attracted to the drum with a force that is ten times the weight of the particle.

What is the ratio of the mass of a toner particle to the magnitude of its net charge?

If the toner particles are made of carbon, how many carbom atoms are there for each excess electron on a toner particle?
 
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The ratio of the mass of a toner particle to the magnitude of its net charge is not possible to calculate without additional information. If the toner particles are made of carbon, there would be 6 x 10^23 carbon atoms for each excess electron on a toner particle.
 

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