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HELP on Hardy Weinberg Problem

  1. Feb 11, 2008 #1
    HELP on Hardy Weinberg Problem!!

    1. The problem statement, all variables and given/known data

    the allel for unattached earlobes is dominant over the allele for attached earlboes. in a population of 500 individuals 25% show the recessive pheontype. how many individuals woul you expect to be homozygous dominant and heterozygous for this trait?

    2. Relevant equations

    p^2+q^2=1.0
    p^2+2pq+q^2=1.0

    3. The attempt at a solution

    q^2=.25
    p^2+.25=1.0
    p^2=.75
    .75 x 500

    p^2 =375 people are homozygous dominant


    square root of .75 = .87
    square root of .25 =.5
    2(.87)(.5)
    .87
    .87 X 500 =435 people are heterozygous

    this on one of my many attempts with this problem. i REALLY need some help with it. someone to walk me step by step through it. i know the equation, i have spent plenty of time working on it and i have more of the same problems so if i dont understand one of them than i cant do any. i have looked through all my text books and am unable to understand it. so if you could please help me out and help me step by step with so i can understand how to apply the formula to the problem i would really appreciate it. thank you
     
  2. jcsd
  3. Feb 12, 2008 #2

    jim mcnamara

    User Avatar
    Science Advisor
    Gold Member

    So now you have template to work these problems.
     
  4. Feb 12, 2008 #3
    thank you VERY much for helping me. i understand it now. thank you. :)
     
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