Help understanding this approximation

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The discussion centers on the analytic approximation of the number of "e-foldings" (N_e) as presented in equation (4.31) from a specific paper. The approximation utilizes an asymptotic expansion with respect to the inverse of N_e, resulting in the expression for e^y. The notation $O$ refers to Big O notation, which describes the limiting behavior of a function. Participants recommend consulting the work of Hinch for a deeper understanding of asymptotic expansions.

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In a paper that I'm reading, the authors write:-

N_e \approx \frac{3}{4} (e^{-y}+y)-1.04 ------------ (4.31)

Now, an analytic approximation can be obtained by using the expansion with respect to the inverse number of "e-foldings" (N_e is the number of "e-foldings"). For instance, eq. (4.31) yields:-

e^y = \dfrac{3}{4N_e} - \dfrac{9ln(N_e)}{16(N_e)^2} -\dfrac{0.94}{(N_e)^2} + O(\dfrac{ln^2(N_e)}{(N_e)^3})

Can anyone tell me how this approximation is done? I'm not familiar with the $O$ notation either. What does it mean? How do the authors arrive at that expression?

If anyone should require it, the original paper can be found here: https://arxiv.org/pdf/1001.5118.pdf?origin=publication_detail
 
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Ryuzaki said:
In a paper that I'm reading, the authors write:-

N_e \approx \frac{3}{4} (e^{-y}+y)-1.04 ------------ (4.31)

Now, an analytic approximation can be obtained by using the expansion with respect to the inverse number of "e-foldings" (N_e is the number of "e-foldings"). For instance, eq. (4.31) yields:-

e^y = \dfrac{3}{4N_e} - \dfrac{9ln(N_e)}{16(N_e)^2} -\dfrac{0.94}{(N_e)^2} + O(\dfrac{ln^2(N_e)}{(N_e)^3})

Can anyone tell me how this approximation is done?


It's an asymptotic expansion. Finding these is more of an art than a science. Hinch is a good introduction.

I'm not familiar with the $O$ notation either. What does it mean?

See http://en.wikipedia.org/wiki/Big_O_notation.
 

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