1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Help with a question regarding Gravimetric Calculations

  1. Jun 11, 2015 #1
    This is the question I have been working through and I just want to know if I am on the right track. Any advice is appreciated.

    10. The major industrial method for the preparation of elemental phosphorus is heating a mixture of phosphate rock, carbon, and sand in an electric furnace. The chemical reactions can be represented by

    Ca3(PO4)2 + SiO2 → CaSiO3 + P4O10

    and

    P4O10 + C → P4 + CO

    a. First balance the equations.

    b. Then calculate the percentage of Ca3(PO4)2 initially present in the rock sample if 307 kg of phosphate rock yields 42.5 kg of elemental P4.

    A) I balanced the equations:

    2Ca3(PO4)2 + 6SiO2 → 6CaSiO3 + P4O10

    and

    P4O10 + 10C → P4 + 10CO

    B) Then I started to work backwards to figure out part B, below are the steps I took.

    moles of P4 = 42.5kg x 1mol P4/ 123.88 g = 343.07 mol

    Moles P4O10 = 343.07 mol x 1mol P4O10/1 mol P4 = 343.07 mol

    kg P4O10 = 343.07 mol x 283.88g/ 1 mol P4O10 = 97.4 kg P4O10

    moles Ca3(PO4)2 = 343.07 mol P4O10 x 2mol Ca3(PO4)2/1mol P4O10 = 686.14 mol

    g Ca3(PO4)2 = 686.14 mol Ca(PO4)2 x 309.94 g/1mol Ca(PO4)2 = 212.66 kg Ca3(PO4)2

    Percent of Ca3(PO4)2 present in original sample = 212.66 kg/307 kg x 100% = 69.2%
     
  2. jcsd
  3. Jun 17, 2015 #2

    Borek

    User Avatar

    Staff: Mentor

    Looks OK to me. Note: to simplify calculations whole process can be written as

    Ca3(PO4)2 → 2P

    (look at the number of atoms of P). While it is not balanced it correctly preserves the ratio between the starting substance and the product you are interested in, making calculations much faster.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Help with a question regarding Gravimetric Calculations
Loading...