Help with Abstract Algebra: Show ac=b, da=b w/Hint

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SUMMARY

The discussion focuses on proving the existence of elements c and d in a group G such that ac = b and da = b for given elements a and b in G. The solution involves defining c as a = a^(-1)b and d as d = ba^(-1). The proofs utilize properties of group elements, specifically the existence of inverses and the cancellation law. The participants confirm the correctness of their approach, emphasizing the importance of explicit definitions for c and d.

PREREQUISITES
  • Understanding of group theory concepts, particularly group operations and inverses.
  • Familiarity with the cancellation law in groups.
  • Basic knowledge of mathematical proofs and definitions.
  • Ability to manipulate algebraic expressions within the context of groups.
NEXT STEPS
  • Study the properties of group inverses in detail.
  • Learn about the cancellation law in group theory.
  • Explore explicit constructions in abstract algebra, particularly in groups.
  • Review examples of proofs involving group operations and element definitions.
USEFUL FOR

Students and educators in abstract algebra, mathematicians focusing on group theory, and anyone seeking to understand the foundational properties of groups and their applications in proofs.

patelnjigar
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Please I need your help for that qustion and how do slove that qustion's problem. can you help me for slove for that? Pleasee

Let G be any group, and let a, b ∈ G. Show that there are c, d ∈ G such that ac = b and da = b. Hint: you have to give an explicit definition for c and d in terms of a and b.
 
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what have you tried?
 
I have tried set up matrices for that but not work. I don't know how to slove for this problem...


Let G be any group, and let a, b ∈ G. Show that there are c, d ∈ G such that ac = b and da = b. Hint: you have to give an explicit definition for c and d in terms of a and b.
 
Matrices?? All you need is:
(i) if x is in G, then so is its inverse
(ii) if x,y are in G, then so is xy
 
i m tried work on this..

GIVE a, b ∈ G
SHOW c, d ∈ G ?

ac=b da=b

ac=b ---> proof: a (a^(-1)b)=b (IS THAT RIGHT? I THINK SO AND THAT'S RIGHT)

da=b ---> proof: ?
 
if i want to say about ac=b

proof: a (a^(-1)b)=b
uniqueness
if ac=ad=b
then c=d (left Cancellation)

How do I slove for da=b?? I need for that..
 
Same idea: let d = ba^(-1).
 
Same idea: let d = ba^(-1). ?? I seem that not enough

ac=b
a (a^(-1)b)=b, if ac=ad=b, then c=d (left cancellation).. I m sure that's right.



da=b
d=ba(a^(-1)), if ad=ac=b, then d=c (right cancellation) is that right?
 

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