Help with carbon dating question please

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cd95
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desperately need help with the question below. me and my dad have been working on it for hours but keep getting the answer to be 5.97x10^-23?! totally off what it should be.

Q. There are about 1.3x10^-12 carbon-14 atoms for each atom of carbon-12 in living materials, and the half-life of carbon-14 is 5730 years. Show that the number of disintegrations occurring in 1 mole of carbon from a living organism is 2.3 per second.

Thanks

Charley
 
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this is what we worked out...

(1.3x10^-12) x 12 = 1.56x10^-11 gm C14/gm C

then using the equation Kb=ln2/half-life...

Kb=ln2/(1.80x10^11) seconds = 3.85x10^-12 disintegrations per second

Then...
(3.85x10^-12) x (1.56x10^-11) = 5.97x10^-23

what have we missed?