Help with Chem rate of reaction problem

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The reaction involves the conversion of 4 moles of PH3 to produce 1 mole of P4 and 6 moles of H2. Given that 0.0063 moles of PH3 are consumed per second, stoichiometry can be applied to determine the rates of production for P4 and H2. For every 4 moles of PH3 consumed, 1 mole of P4 is produced, resulting in a production rate of 0.001575 moles of P4 per second. Simultaneously, for every 4 moles of PH3 consumed, 6 moles of H2 are produced, leading to a production rate of 0.00945 moles of H2 per second. This analysis effectively utilizes stoichiometric relationships to find the rates of product formation.
pata320
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4PH3(g) ------- P4(g) + 6H2(g)
If, in a certain experiment, over a specific time period, 0.0063 mol PH3 is consumed in a 2.0 L container each second of reaction, what are the rates of production of P4 and H2 in this experiment.

Any idea about this problem? divide 2.0 to 1.0 and then .0063 to .00315 but from there I have no clue. Anybody have a clue? Thanks a bunch!
 
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pata320 said:
4PH3(g) ------- P4(g) + 6H2(g)
If, in a certain experiment, over a specific time period, 0.0063 mol PH3 is consumed in a 2.0 L container each second of reaction, what are the rates of production of P4 and H2 in this experiment.

the rate of consuming of PH3 is 0,0063 mol / s. Now use stoichiometry to get to know the rates of formation of P4 and H2:

1. when 4 mol PH3 has reacted, then 1 mol P4 is formed --> How much P4 is formed per second when 0,0063 mol PH3 has reacted (per second) ?

2. when 4 mol PH3 has reacted, then 6 mol H2 is formed --> How much H2 is formed per second when 0,0063 mol PH3 has reacted (per second) ?
 

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