4PH3(g) ------- P4(g) + 6H2(g) If, in a certain experiment, over a specific time period, 0.0063 mol PH3 is consumed in a 2.0 L container each second of reaction, what are the rates of production of P4 and H2 in this experiment. Any idea about this problem? divide 2.0 to 1.0 and then .0063 to .00315 but from there I have no clue. Anybody have a clue? Thanks a bunch!