Hi there,
Thank you for reaching out for help with your confusing fluid problem. I can understand how the question may seem overwhelming at first, but with some guidance, I'm sure you will be able to solve it.
Firstly, let's break down the information given in the problem. We have a 5/8 inch diameter hose, a round swimming pool with a diameter of 7.2 m, and a desired depth of 44 inches. We also know that the water is flowing out of the hose at a speed of 0.28 m/s.
To solve this problem, we will need to use the formula for volume of a cylinder (V=πr^2h) and the formula for flow rate (Q=Av). Let's start by converting all the measurements to the same unit - meters.
5/8 inch is equivalent to 0.015875 meters (to convert inches to meters, divide by 39.37).
The diameter of the pool is 7.2 m, so the radius (r) will be half of that, which is 3.6 m.
The desired depth of 44 inches is equivalent to 1.118 meters (to convert inches to meters, divide by 39.37).
Now, we can plug these values into the formula for volume of a cylinder:
V=π(3.6)^2(1.118)
V=45.81 m^3
Next, we will use the formula for flow rate to find out how much water is coming out of the hose per second:
Q=0.015875 * 0.28
Q=0.00445 m^3/s
To find out how long it will take to fill the pool, we need to divide the volume of the pool by the flow rate:
45.81/0.00445=10,317.98 seconds
Since we want the time in minutes, we can divide this by 60:
10,317.98/60= 171.97 minutes
Therefore, it will take approximately 172 minutes to fill the pool to a depth of 44 inches using a 5/8 inch diameter hose with a water speed of 0.28 m/s.
I hope this helps you understand the problem better and gives you a place to start. Remember to always write down the given information and identify the formulas you need to use before attempting to solve the problem. Good luck!