Help With Find The Cardinality of a Power Set of a Cartesian Product

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Homework Help Overview

The discussion revolves around determining the cardinality of the power set of a Cartesian product of two finite sets, A and B, specifically focusing on |P(AxB)| and |P(A)xP(B)|.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to establish that |P(AxB)| can be calculated as 2^(|A| * |B|) based on the properties of power sets and Cartesian products. Other participants confirm the correctness of this approach. Another participant raises a related question about |P(A)xP(B)|, seeking clarification on whether it can be discussed within the same thread.

Discussion Status

Participants are actively engaging with the original problem and related queries. Some have confirmed the correctness of the initial reasoning, while others are exploring the implications of the related question about |P(A)xP(B)|. There is a productive exchange of ideas regarding the relationships between the sets and their power sets.

Contextual Notes

Participants are navigating the nuances of set theory, particularly focusing on the cardinalities of power sets and Cartesian products. There is an acknowledgment of the finite nature of the sets involved, which influences the discussions and calculations presented.

daneault23
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Homework Statement



Suppose that A and B are finite sets.
What is |P(AxB)|? Meaning what is the cardinality of the power set of a cartesian product of the sets A and B.


Homework Equations



|AxB|=|A| * |B| since A and B are finite sets
Power set of a set is the set of all subsets of that set, including the empty set and the set itself
There are 2^|A| subsets for a set A when A is finite


The Attempt at a Solution



Since A and B are finite sets, we have |AxB|=|A| * |B|. Now the power set of (AxB) is the set of all its subsets, including the empty set and the set AxB itself. Since A and B are both finite sets, there is also a finite number of subsets of (AxB). By letting C=AxB, there are exactly 2^|C| subsets. Thus |P(AxB)|=2^|AxB|=2^(|A| * |B|)

This is what I have.
 
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That's just fine.
 
I have a similar question asking what the |P(A)xP(B)| is. Can I ask that in this thread, or do I have to start another thread?
 
daneault23 said:
I have a similar question asking what the |P(A)xP(B)| is. Can I ask that in this thread, or do I have to start another thread?

You never HAVE to start another thread. It's usually recommended if the problem is unrelated but this one isn't. Ask here.
 
The question asks what is |P(A)xP(B)|. This is asking what is the cardinality of the cartesian product of the power set of A and power set of B. I'm having some trouble deciphering this.

I let C=P(A) and D=P(B). Then, |CxD|=|C| * |D| since once again A and B are both finite sets, meaning their respective power sets, C and D, are also finite sets.

So, |P(A)xP(B)|=2^C * 2^D

That is what I have.
 
No problem again. That's correct.
 
Dick said:
No problem again. That's correct.

Dick, are you saying that the syntax or form looks correct, or do you believe that is the correct answer?

So simplyifying it, it would be |P(A)xP(B)|=2^|C| * 2^|D|=2^2^|A| * 2^2^|B|
 
daneault23 said:
Dick, are you saying that the syntax or form looks correct, or do you believe that is the correct answer?

So simplyifying it, it would be |P(A)xP(B)|=2^|C| * 2^|D|=2^2^|A| * 2^2^|B|

No, I was reading too fast. It's 2^|A|*2^|B|. |C|=2^|A| and |D|=2^|B|. |CxD|=|C||D|.
 
Last edited:

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