Help with finding all real solutions

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Homework Help Overview

The discussion revolves around finding all real solutions to the polynomial equation x^4 - 8x^2 + 2 = 0, which can be approached through methods related to quadratic equations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the use of the quadratic formula and substitution methods, questioning the applicability of these techniques to the given polynomial form. There is discussion about transforming the equation into a quadratic form by substituting t = x^2.

Discussion Status

Some participants have suggested using the factor/remainder theorem and highlighted the importance of considering only real solutions, while acknowledging the existence of complex roots. There is an ongoing exploration of different interpretations and methods without a clear consensus on the best approach.

Contextual Notes

Participants note the relevance of the thread title, which emphasizes finding real solutions, thereby suggesting that complex solutions may not be necessary for this discussion.

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Homework Statement


x^4 - 8x^2 + 2 = 0

Homework Equations


quadratic formula?

The Attempt at a Solution


i would've tried using the quadratic formula, but I am not sure if this would work with that seeing as how it's not ax^2 + bx + c
 
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You will need to use the factor/remainder theorem.
 
The example equation is in quadratic form, or something like it. First, you may use a substitution, something like, t=x^2. This can give you like, this:

t^2 - 8t + 2 = 0

Now, you can solve THAT one and you may obtain two solutions, but those solutions are for t. Now, solve each of those solutions for x (remember to first replace t with x^2 )
 
The polynomial fortunately is quadratic, but in x2.

If u = x2 then you have x4 -8x2 + 2 = u2 - 8u + 2 = 0.

You can use the quadratic formula to solve for x2 keeping in mind that any negative roots from the formula must be discarded since x2 can never be negative.

--Elucidus
 
Elucidus said:
...keeping in mind that any negative roots from the formula must be discarded since x2 can never be negative.

--Elucidus

We have this field now called complex numbers that has negitive squares.
i^2=-1 for example
 
lurflurf said:
We have this field now called complex numbers that has negitive squares.
i^2=-1 for example

The thread title is "help with finding all real solutions" so I figured that complex solutions weren't needed.

--Elucidus
 
Elucidus said:
The thread title is "help with finding all real solutions" so I figured that complex solutions weren't needed.

--Elucidus

Good point. I like to keep track of the complex roots to assist in tracking the real roots. The fundamental theorem of a algebra impies each complex root means one less real root to find.
 

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