Help with Hagen-Poiseuille Flow

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SUMMARY

The discussion focuses on deriving the velocity profile for Hagen-Poiseuille flow through a pipe using the Navier-Stokes equations. The primary result indicates that the axial velocity, vz, is given by the equation vz = (1/4η)(∂p/∂z)(ρ² - R²), where R is the pipe radius. The user questions the necessity of incorporating the equations for the radial (ρ) and azimuthal (φ) directions, which are typically used in parallel plate flow analysis. The response clarifies that for fully-developed flow, the velocity profile can be derived without these additional equations, emphasizing the importance of understanding the continuity and momentum equations in cylindrical coordinates.

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  • Understanding of Navier-Stokes equations
  • Familiarity with cylindrical coordinates
  • Knowledge of fluid dynamics concepts, specifically Hagen-Poiseuille flow
  • Ability to perform non-dimensional analysis
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  • Study the derivation of the Hagen-Poiseuille equation in detail
  • Learn about fully-developed flow conditions in cylindrical geometries
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  • Investigate the application of the Laplacian operator in cylindrical coordinates
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Fluid mechanics students, engineers working with pipe flow, and researchers in fluid dynamics will benefit from this discussion, particularly those focusing on velocity profiles and flow analysis in cylindrical systems.

teeeeee
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Hi

I'm trying to derive the velocity profile for Hagen-Poiseuille flow through a pipe.
Using cylindrical coordinates (z direction horizontal), I began by applying the Navier-Stokes equations to each coordinate.

For z, I got: \frac{1}{\eta} \frac{\partial p}{\partial z} = \frac{1}{\rho} \frac{\partial}{\partial\rho} (\rho \frac{\partial v_{z}}{\partial\rho}) and from this equation I got the result that v_{z} = \frac{1}{4\eta} \frac{\partial p}{\partial z} (\rho^{2} - R^{2}) where R is the radius of the pipe

The Navier-Stokes equations for the \rho and \phi directions give \frac{\partial p}{\partial \rho} = \mu g_{\rho} and \frac{\partial p}{\partial \phi} = \mu g_{\phi} respectively, where g is gravity in each direction and \mu is the density of the fluid.

I know that when deriving the velocity profile for flow between parallel plates, you need to use the \phi and \rho equations to show what is a function of what, and what is independent of what.
However, I've managed to get the velocity profile without using any information from the other two coordinate equations. Have I missed something? Do I need to use these two equations for something?

Many thanks
teeeeee
 
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Let me walk you from the beginning. If we assume fully-developed flow, then the velocity becomes purely axial, and varies only with the lateral coordinates, that is:
<br /> \begin{equation}<br /> \begin{split}<br /> v=w=0 \\<br /> u=u(y,z)<br /> \end{split}<br /> \end{equation}<br />
The continuity and momentum equations can then reduce to:
<br /> \begin{equation}<br /> \begin{split}<br /> \frac{\partial u}{\partial x}=0 \\<br /> -\frac{\partial \hat{p}}{\partial x} + \mu\left(\frac{\partial^2 u}{\partial y^2} + \frac{\partial^2 u}{\partial z^2}\right) = 0 \\<br /> -\frac{\partial \hat{p}}{\partial y} = -\frac{\partial \hat{p}}{\partial y}<br /> \end{split}<br /> \end{equation}<br />
These indicate that the total pressure is a function only of x. Since u does not vary with x, we can say that the gradient dp*/dx must be a negative constant. Then, we can combine to form the basic equation as:
<br /> \frac{\partial^2 u}{\partial y^2} + \frac{\partial^2 u}{\partial z^2} = \frac{1}{\mu}\frac{d\hat{p}}{dx} = \mbox{const}<br />
We can then non-dimensionalize as:
<br /> \begin{equation}<br /> \begin{split}<br /> y* &amp;= \frac{y}{h} \\<br /> z* &amp;= \frac{z}{h} \\<br /> u* &amp;= \frac{\mu u}{h^2(-d\hat{p}/dx)}<br /> \end{split}<br /> \end{equation}<br />
Where h is a characteristic duct width. OK, now that we have those variables defined, we can rewrite the general equation as:
<br /> \nabla^{*2}(u*) = -1<br />

OK, we're just about there. Now, for a Hagen-Poiseuille Fow, we have a circular duct, so the single variable is of course r. Non-dimensionally, we can write r*=r/r_o where r_o is the pipe radius. The Laplacian operator in cylindrical coordiantes reduces to:
<br /> \nabla^2 = \frac{1}{r}\frac{d}{dr}\left(r\frac{d}{dr}\right)<br />

From here you can plug your operator into the general equation using the non-dimensional terms. If you need more help, come back with a good attempt and we can get you the rest of the way.
 

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