MATLAB Help with Math: Calculate Manually, No MATLAB Needed

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The discussion focuses on calculating the derivative and tangent line for the equation y^4 + xy = 2x^2 - 7x + 7. The derivative is derived through implicit differentiation, resulting in the expression dy/dx = (4x - y - 7) / (4y^3 + x). At the point (1, 1), the derivative evaluates to -4/5. Consequently, the equation of the tangent line T(x) is determined to be T(x) = -4/5(x - 1) + 1, simplifying to T(x) = -4/5x + 1/5. This process illustrates the steps involved in finding the tangent line to a curve defined by an implicit function.
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Can someone help me with this? You don't need to do MATLAB, just compute manually.
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Have you calculated T(x)? You are given $y^4+ xy= 2x^2- 7x+ 7$. Differentiating, $4y^3\frac{dy}{dx}+ y+ x\frac{dy}{dx}= 4x- 7$. $4y^3\frac{dy}{dx}+ x\frac{dy}{dx}= (4y^3+ x)\frac{dy}{dx}= 4x- y- 7$. $\frac{dy}{dx}= \frac{4x- y- 7}{4y^3+ x}$. At (1, 1), $\frac{dy}{dx}= \frac{4- 1- 7}{4+ 1}= \frac{-4}{5}$. $T(x)= -\frac{4}{5}(x- 1)+ 1= -\frac{4}{5}x+ \frac{1}{5}$.
 

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