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Help with my big oh algorithm analaysis

  1. Mar 17, 2012 #1
    for(int i = 0; i < n; i++){
    for(int j = 0; j < n; j++){
    if (i == j){
    for(int k = 0; k < n*n; k++){
    System.out.println();
    }
    }
    else{
    for(int h = 1; h <= n; h = h*2){
    System.out.println();
    }
    }
    }​
     
  2. jcsd
  3. Mar 17, 2012 #2
    Any attempt at a solution? Where have you gotten so far? As a small hint, O(n) is the worst case, so look at those loops and think where the most steps can be taken.
     
  4. Mar 17, 2012 #3
    i know the answer is n3 + n2log2n - nlog2n but i have no idea how to get this far
    I know the loops runs n^2 times at least but im not sure how to do the if statements
     
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