Help with simple momentum derivation

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The discussion focuses on deriving the final velocity V1 for an elastic collision between two objects using conservation of momentum and energy equations. The key approach involves changing the frame of reference to the center of momentum frame, where the velocities of the objects can be simplified. By calculating the appropriate velocity shift and negating the resulting velocities, the final velocities can be expressed in terms of the initial velocities and masses of the objects. Participants emphasize the algebraic manipulation required to arrive at the desired equation, suggesting that it may be easier to visualize the problem in the center of momentum frame. The conversation highlights the importance of understanding the underlying physics and algebra in solving collision problems.
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Hi, I read this equation under elastic collisions in Wikipedia but I can't figure out how they derived it.

Homework Statement


For an elastic collision of two objects, show that the final velocity V1 is given by
V1 = [U1*(m1-m2) + 2*m2*U2]/[m1+m2]

where U1 = initial velocity of object1, U2 = initial velocity of object2 (known)
m1 = mass of object1 , m2 = mass of object2 (known)

Homework Equations



m1*U1 + m2*U2 = m1*V1 + m2*V2 (conservation of momentum)

[m1*U1^2]/2 + [m2*U2^2]/2 = [m1*V1^2]/2 + [m2*V2^2]/2 (conservation of energy)

The Attempt at a Solution



On Wiki, it said to change the frame of reference to make one of the unknown velocity, V1 or V2, equal to zero and solve for the other unknown velocity in the two conservation equations. I made V1 zero and juggled with a lot of algebra using substitution but couldn't arrive at anything similar to the above equation.
 
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bsin said:
Hi, I read this equation under elastic collisions in Wikipedia but I can't figure out how they derived it.

Homework Statement


For an elastic collision of two objects, show that the final velocity V1 is given by
V1 = [U1*(m1-m2) + 2*m2*U2]/[m1+m2]

where U1 = initial velocity of object1, U2 = initial velocity of object2 (known)
m1 = mass of object1 , m2 = mass of object2 (known)

Homework Equations



m1*U1 + m2*U2 = m1*V1 + m2*V2 (conservation of momentum)

[m1*U1^2]/2 + [m2*U2^2]/2 = [m1*V1^2]/2 + [m2*V2^2]/2 (conservation of energy)

The Attempt at a Solution



On Wiki, it said to change the frame of reference to make one of the unknown velocity, V1 or V2, equal to zero and solve for the other unknown velocity in the two conservation equations. I made V1 zero and juggled with a lot of algebra using substitution but couldn't arrive at anything similar to the above equation.
You have 2 equations with 2 unknowns, so you have a solvable solution.
But it is not that simple to solve the 2 simultaneous equations. Just keep on surfing around for an explanation you are comfortable with. It's 'just' :wink: algebra.
 
bsin said:
Hi, I read this equation under elastic collisions in Wikipedia but I can't figure out how they derived it.

Homework Statement


For an elastic collision of two objects, show that the final velocity V1 is given by
V1 = [U1*(m1-m2) + 2*m2*U2]/[m1+m2]

where U1 = initial velocity of object1, U2 = initial velocity of object2 (known)
m1 = mass of object1 , m2 = mass of object2 (known)

Homework Equations



m1*U1 + m2*U2 = m1*V1 + m2*V2 (conservation of momentum)

[m1*U1^2]/2 + [m2*U2^2]/2 = [m1*V1^2]/2 + [m2*V2^2]/2 (conservation of energy)

The Attempt at a Solution



On Wiki, it said to change the frame of reference to make one of the unknown velocity, V1 or V2, equal to zero and solve for the other unknown velocity in the two conservation equations. I made V1 zero and juggled with a lot of algebra using substitution but couldn't arrive at anything similar to the above equation.

I find that it is easier to change the frame of reference to the center of momentum frame. In the COM frame, the collision is between two objects carrying equal and opposite momentum. This means that both objects "bounce", simply reversing their velocities.

So the procedure is:

1. Convert the initial velocities to the center of momentum frame.
2. Negate the resulting velocities.
3. Convert back to the original frame of reference.

Step 1 amounts to finding a velocity u to add to each initial velocity so that

(U1 + u)*m1 = -(U2 + u)*m2

Solve for u: u = -(m1*U1 + m2*U2)/(m1 + m2)

Step 2 says negate the resulting velocities:

v1 = -(U1 + u) and v2 = -(U2 + u)

Step 3 says convert back to original frame of reference:

V1 = v1 - u and V2 = v2 - u

Putting steps 2 & 3 together:

V1 = -(U1 + 2*u) and V2 = -(U2 + 2u)

I think that if you substitute the value for u from above into these expressions that you'll find the desired derived expressions.
 
I am not sure if it is accurate but I think of it like think assuming there is change in velocity
v1m1+u1m2=v2m1+u2m2


v1m1-v2m1=u2m2-u1m2
m1(v1-v2)= m2(u2-u1)

.5m1v21+.5m2u21=.5m1v22+.5m2u22

m1v21+.m2u21=m1v22+m2u22

then solve the two equations
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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