Help with special relativity problem (off by a factor of 2)

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Homework Help Overview

The problem involves calculating the cost of tritium needed to heat a large swimming pool using a fusion reaction, framed within the context of special relativity. The original poster attempts to determine the total energy required and the cost based on the efficiency of the heating system and the energy produced per reaction.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the calculations related to energy requirements and the efficiency of the heating system. There is a focus on the interpretation of units, specifically the distinction between atoms and molecules in the context of gas calculations.

Discussion Status

Some participants have provided guidance regarding the correct interpretation of the units involved, suggesting that the original poster's misunderstanding may have led to the discrepancy in the final cost calculation. Multiple interpretations of the problem setup are being explored, particularly concerning the assumptions about the fusion process and the associated costs.

Contextual Notes

Participants note that the problem's setup may seem unrealistic, and there are references to the original poster's uncertainty about their chemistry knowledge, which may affect their understanding of the problem.

weston.pace
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Homework Statement



Special Relativity A.P French Problem 1-9

An eccentric billionaire decides to sterilize his 106 liter swimming pool by boiling the water in it. For heating purposes he uses the fusion reaction:

1H + 3H → 4He + radiant energy

Assuming the heating system is 20% efficient, how much does he pay for the tritium (3H) to raise the pool temperature from 20°C to 100°C? It takes 4.2 joules to raise 1g of water through 1°C. Tritium costs about $5 per cm3 of gas at STP.

Homework Equations



E = mc2

The Attempt at a Solution



Total energy required:
E_{total} = 4.2 \frac{J}{g°C} * 10^9 g * 80°C = 3.36*10^{11} J

Energy Generated per reaction:
E_{reaction} = m_{diff} * c^{2}
E_{reaction} = ((1.0081 + 3.0170) - 4.0039)amu * 1.6603*10^{-27} * (3*10^{8}\frac{m}{s})^{2} = 3.1682 * 10^{-12} J

Atoms per cubic centimeter of gas at STP:

\frac{atoms}{cm^3}=6.0221*10^{23} * \frac{1}{22.711} * 10^{-3} = 2.6516 * 10^{19}

Final Result (1/0.2) is to account for 20% efficiency:
cost=$5*\frac{1}{0.2} * \frac{E_{total}}{\frac{E_{reaction}}{\frac{atoms}{cm^3}}} =~ $100,000

The answer in the book is $50,000, which would imply I'm off by a factor of two. I've looked over this for some time and can't see my mistake. Can anyone help me spot what I've missed?
 
Last edited:
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It is "molecules per cubic centimeter", not atoms.

Tritium gas is T2.
That is a weird setup. He will spend the first billion (at least) for the fusion reactor.
 
mfb said:
That is a weird setup. He will spend the first billion (at least) for the fusion reactor.

I think irrationality is a requirement in physics textbooks problems.

Thanks for the help, that would certainly yield the right answer. Is this just something that should have been obvious from a chemistry standpoint? My chemistry is really rusty.
 
Hmm... it is something you should know, but there is a big difference between knowing it and thinking of it.
 
weston.pace said:
Is this just something that should have been obvious from a chemistry standpoint? My chemistry is really rusty.

Chemistry or physics, the thing to remember is that gases are made of molecules, and the Avogadro constant is how many molecules a mole of gas contains. Then you just need to find what a molecule of the given gas is.
 

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