Help with standing waves question

Click For Summary
SUMMARY

The discussion centers on the calculation of the wavelength of sound produced by a loudspeaker emitting a frequency of 425 Hz above a glass tube filled with water. When the water level drops to 20 cm, a standing wave forms, indicating that the air column resonates at this length. The wavelength is determined using the formula v = fλ, leading to a wavelength of 80 cm, as λ/4 equals 20 cm. The participants confirm that the standing wave at this length corresponds to the fundamental frequency, as shorter lengths would resonate at higher harmonics.

PREREQUISITES
  • Understanding of wave mechanics and sound propagation
  • Familiarity with the concepts of standing waves and harmonics
  • Knowledge of the relationship between frequency, wavelength, and wave speed
  • Basic mathematical skills for solving equations related to wave properties
NEXT STEPS
  • Study the principles of standing waves in closed tubes
  • Learn about harmonic frequencies and their calculations
  • Explore the relationship between frequency, wavelength, and wave speed in different mediums
  • Investigate practical applications of sound waves in acoustics
USEFUL FOR

Students and educators in physics, acoustics engineers, and anyone interested in the principles of sound waves and resonance in closed systems.

Vandalus
Messages
7
Reaction score
0
A small loudspeaker connected to a signal generator emits a sound of frequency 425 Hz. It is fixed above a long glass tube that is filled with water and has a drain at the bottom so that the water can be slowly released from it. When the level has fallen 20cm from the top of the tube, a standing wave is formed and the air column resonates.

Calculate the wavelength of the sound.

v = fλ

In my book's worked example it says that:

λ/4 = 20cm therefore the λ must be 80cm.

What I don't understand is this:

How do you know that at 20 cm, the standing wave generated will definitely be the first harmonic/fundamental frequency since λ/4 only applies if the standing wave generated is the fundamental frequency?

Isn't 20cm just an arbitrary number?

Or is it that no matter how much the water level falls (no matter the length of the closed tube) the first input of sound will definitely be the fundamental frequency?

Any help is greatly appreciated :D
 
Physics news on Phys.org
Vandalus said:
Or is it that no matter how much the water level falls (no matter the length of the closed tube) the first input of sound will definitely be the fundamental frequency?

Yes. It's the (implied) fact that it did not resonate at any shorter length. Had 20cm been, say, the third harmonic, it would have resonated at 4cm.
 
Ah ok. Looks like I should learn to read questions more thoroughly aha.

Thanks :D
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
5
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
3
Views
4K
  • · Replies 5 ·
Replies
5
Views
6K