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Help with this subbing equation to another equation question

  1. Sep 27, 2009 #1
    1. The problem statement, all variables and given/known data

    runner A runs at 6.0 m/s for 10s. Runnber B accelerates from 4.0 m/s to 10.0 m/s. steadily. in 10s.
    how far does runner a go?

    2. Relevant equations

    v2=v1+at
    d=v1*t+0.5a*t^2
    d=Vavg*t

    3. The attempt at a solution
    ok this is how much i've worked it out so far
    but i'm stuck now
    v2=v1+at
    a=(v2-v1)/2
    v1=6m/s
    t=10s
    d=v1*t+0.5at^2
    d=6*10+0.5((v2-6)/10)*10^2
    does 0.5 multiply the denominator?
    am i even doing this right?
     
  2. jcsd
  3. Sep 27, 2009 #2

    Delphi51

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    d = vt = 6*10 = 60 m
     
  4. Sep 27, 2009 #3
    so... >_> it was that simple.. >< But does the 0.5 multiply the denominator? Also is the 0.5 in this case the coefficient? Is that a coefficient?
     
  5. Sep 27, 2009 #4

    Delphi51

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    Hmm, too simple. Is there a part (b)? It might, for example, ask how far ahead one runner is after the 10 seconds.
     
  6. Sep 27, 2009 #5
    Hm well part b was How far does runner B go? Found out it was 70

    Now i'm stuck with this question. Do i start a new thread or do i post it here and just edit it?
     
  7. Sep 27, 2009 #6

    Delphi51

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    I agree with the 70.
    Sorry about the delay; I had to lop two 6 inch branches off a tree 25 feet up!
    Success, except I crashed one of them on my gate and damaged it.
     
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