Help with this subbing equation to another equation question

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Homework Help Overview

The problem involves two runners, A and B, with runner A running at a constant speed and runner B accelerating over a set time. The participants are exploring the distance covered by each runner within the same time frame.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of kinematic equations to determine the distances traveled by each runner. Questions arise regarding the interpretation of coefficients in the equations and the validity of the calculations performed.

Discussion Status

Some participants have confirmed the distance covered by runner A as 60 meters, while others are exploring the implications of the calculations for runner B's distance. There is an ongoing dialogue about whether to continue the discussion in the same thread or start a new one for additional questions.

Contextual Notes

Participants are considering potential follow-up questions related to the problem, such as comparing the distances covered by both runners after the same time interval. There is also mention of a possible part (b) to the problem that has not been fully defined.

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Homework Statement



runner A runs at 6.0 m/s for 10s. Runnber B accelerates from 4.0 m/s to 10.0 m/s. steadily. in 10s.
how far does runner a go?

Homework Equations



v2=v1+at
d=v1*t+0.5a*t^2
d=Vavg*t

The Attempt at a Solution


ok this is how much I've worked it out so far
but I'm stuck now
v2=v1+at
a=(v2-v1)/2
v1=6m/s
t=10s
d=v1*t+0.5at^2
d=6*10+0.5((v2-6)/10)*10^2
does 0.5 multiply the denominator?
am i even doing this right?
 
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runner A runs at 6.0 m/s for 10s.
d = vt = 6*10 = 60 m
 
so... >_> it was that simple.. >< But does the 0.5 multiply the denominator? Also is the 0.5 in this case the coefficient? Is that a coefficient?
 
Hmm, too simple. Is there a part (b)? It might, for example, ask how far ahead one runner is after the 10 seconds.
 
Delphi51 said:
d = vt = 6*10 = 60 m

Delphi51 said:
Hmm, too simple. Is there a part (b)? It might, for example, ask how far ahead one runner is after the 10 seconds.

Hm well part b was How far does runner B go? Found out it was 70

Now I'm stuck with this question. Do i start a new thread or do i post it here and just edit it?
 
I agree with the 70.
Sorry about the delay; I had to lop two 6 inch branches off a tree 25 feet up!
Success, except I crashed one of them on my gate and damaged it.
 

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