1. The problem statement, all variables and given/known data Max (65 kg) pushes Toni (50 kg) with a force of 360 N. The force of friction is 0 on Toni and 80 on Max. (a) Find each girls acceleration (b) If Max pushes Toni for 0.1 s, how far will Toni travel in 0.5 s? 2. Relevant equations Fnet=ma v2=v1+at d=v1(t)+1/2a(t)^2 3. The attempt at a solution For (a), I got the correct answers by using Fnet=ma Max's acceleration:4.3m/s^2 (left) Toni's acceleration: 7.2m/s^2 (right) For (b), Toni's acceleration is only 7.2 during the 0.1 seconds so... d=v1(t)+1/2a(t)^2 d=(0)(0.1)+1/2(7.2)(0.1)^2 d=0.036 To find the distance for the remaining 0.4 seconds, I need to find v1 which is v2 of the 0.1 seconds v2=v1+at v2=7.2(0.1) v2=0.72 m/s So v1 for the 0.4 s is 0.72. I assumed acceleration is 0 during this time and that she is now moving at a constant velocity d=0.72(0.4)+1/2(0)(0.4)^2 d=0.288 d1+d2=0.324 It's very close to the answer my teacher gave which is 0.33 m..but I'm just curious as to why it's a little off because it might be considered wrong on a test.