- #1

gungo

- 27

- 1

## Homework Statement

Max (65 kg) pushes Toni (50 kg) with a force of 360 N. The force of friction is 0 on Toni and 80 on Max.

(a) Find each girls acceleration

(b) If Max pushes Toni for 0.1 s, how far will Toni travel in 0.5 s?

## Homework Equations

Fnet=ma

v2=v1+at

d=v1(t)+1/2a(t)^2

## The Attempt at a Solution

For (a), I got the correct answers by using Fnet=ma

**Max's acceleration**:4.3m/s^2 (left)

**Toni's acceleration**: 7.2m/s^2 (right)

For (b), Toni's acceleration is only 7.2 during the 0.1 seconds so...

d=v1(t)+1/2a(t)^2

d=(0)(0.1)+1/2(7.2)(0.1)^2

d=0.036

To find the distance for the remaining 0.4 seconds, I need to find v1 which is v2 of the 0.1 seconds

v2=v1+at

v2=7.2(0.1)

v2=0.72 m/s

So v1 for the 0.4 s is 0.72. I assumed acceleration is 0 during this time and that she is now moving at a constant velocity

d=0.72(0.4)+1/2(0)(0.4)^2

d=0.288

d1+d2=0.324

It's very close to the answer my teacher gave which is 0.33 m..but I'm just curious as to why it's a little off because it might be considered wrong on a test.