Help with Vectors: Calculating Displacement, Speed & Velocity

  • Thread starter Thread starter jesstryin
  • Start date Start date
  • Tags Tags
    Vectors
Click For Summary

Homework Help Overview

The problem involves calculating distance, displacement, average speed, and average velocity based on a series of movements made by Darryl while driving a load of tomatoes. The movements are specified in terms of distances and directions, requiring vector analysis to determine the resultant displacement and velocity.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the calculations for total distance and displacement, with some questioning the accuracy of the displacement calculation. There are inquiries about the correct representation of displacement direction.

Discussion Status

Some participants have confirmed the correctness of the displacement magnitude calculation, while others are exploring the proper way to express the direction of the displacement vector. There is an ongoing dialogue about the nuances of vector representation.

Contextual Notes

Participants are navigating potential miscalculations and clarifying vector definitions, particularly regarding the angles and directions associated with displacement. There is an emphasis on ensuring clarity in the representation of vector quantities.

jesstryin
Messages
8
Reaction score
0

Homework Statement



Hi everyone, my problem is this:

Darryl drives his load of tomatoes 14.0 km [E], 6.0 km [N], 12.0 km [ N 15° E], and then 2.0 km [N 65° E]. This takes him 42 minutes.

a) Calculate Darryl's distance and displacement. Draw a diagram and show your work.
b) Calculate Darryl's average speed and average velocity (record your answer in m/s).

Homework Equations



sinb/b =sinC/C

The Attempt at a Solution



A. 14 km + 6.0 km + 12.0 km + 2.0 km = 34 km
Total Distance is 34 km = 34,000 m

D (east) = 14 + 12 * sin15 + 2 * sin65 = 18.9 km

D (north) = 6 + 12 * cos15 + 2 * cos65 = 18.4 km

C2 =√ a2 + b2
D = √(18.9km² + 18.4km²)
= 26.4 km

My problem is that I think I miscalculated the displacement (east), for the speed and velocity calculation I did this:

B.
Vav (speed) = 34km / 42 min = 34,000 m / 2520 s
Vav= 13.49 or 13.5 m/s


Vav = 26.4 km / 42 min = 26,400 / 2520
Vav (velocity) = 10.47 or 10.5 m/s

I just need clarification for displacement, so that I can accurately calculate the velocity.
 
Physics news on Phys.org
Hi jesstryin. Welcome to Physics Forums.

Your method looks right, though I haven't checked your arithmetic.
 
  • Like
Likes   Reactions: 1 person
Thank you! Could you let me know if I got the answer correct for displacement, I feel like I'm missing a step and need the displacement to calculate the right velocity. Thanks so much!
 
Your displacement magnitude calculation is correct.

Don't forget that vector quantities are specified by a magnitude and a direction.
 
So, is the answer for displacement 26.4 km N 54.9 degrees E ? Or is it 26.4 km E 54.9 degrees N ? I think it is the former, but I am not sure.

Thank you for all the help I appreciate it!
 
jesstryin said:
So, is the answer for displacement 26.4 km N 54.9 degrees E ? Or is it 26.4 km E 54.9 degrees N ? I think it is the former, but I am not sure.
I believe this link explains that.

http://www.compassdude.com/compass-units.shtml
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
6K
Replies
6
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
5
Views
2K