Help with work and energy problem

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SUMMARY

The discussion focuses on solving a physics problem involving a car's stopping distance under different conditions. The first part calculates the horizontal force exerted by a car with a mass of 890.0 kg traveling at 27.0 m/s, resulting in a force of 5402 N using the work-energy principle. The second part explores the stopping distance when the car travels up an 18.9-degree slope, requiring the application of free body diagrams and kinematic equations. The user seeks clarification on how to accurately determine the horizontal distance in this scenario.

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  • Understanding of Newton's laws of motion
  • Familiarity with work-energy principles
  • Knowledge of kinematic equations
  • Ability to create and interpret free body diagrams
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NAkid
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Hi i need help with this problem. The first part asks
A car (m = 890.0 kg) traveling on a level road at 27.0 m/s (60.5 mph) can stop, locking its wheels, in a distance of 60.0 m (196.9 ft). Find the size of the horizontal force which the car applies on the road while stopping on the road. First solve this problem using work/energy concepts and then check your answer using kinematics/force law concepts.

I solved this by finding the acceleration and plugging into formula F=ma=5402N

The second part asks
Find the stopping distance of that same car when it is traveling up a 18.9deg slope, and it locks its wheels while traveling at 27.0 m/s (60.5 mph). Assume that muk does not depend on the speed.

I drew a free body diagram and came up with the following relationships
F-fk-mgsin(18.9)=ma where F=5402N
N-mgcos(18.9)=0

How do I solve for the horizontal distance? Is it just the vertical component of the Force?
 
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I just tried using the formula Vf^2 = v0^2 + 2adx -- where final velocity=0, initial velocity is given, and i solved for a using the above equation F-ukmgcos(18.9)-mgsin(18.9)=ma. But I still didn't get the right answer..
 

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