1. The problem statement, all variables and given/known data A particle of mass 1 kg moves under the force F = 5i + 15t^2j N, where t is in seconds. The initial velocity of the particle is 2i + 3j + 4k ms^−1. Find the work done by the force acting on the particle, and the increase in kinetic energy of the particle , during the time 0 ≤ t ≤ 1. 2. Relevant equations F=ma or F=m(dv/dt)? 3. The attempt at a solution i attempted to use the F=m(dv/dt) and put it equal to the force, so 1(dv/dt)=5i+15t^2, then i integrated to get dx/dt=5ti+15/3*t^3, I then added the initial velocity of 2i+3j+4k, so now had 5ti+15/3*t^3 +2i+3j+4k, now i am thinking this is wrong, but my next plan was to integrate this again, with the limits of 0 to 1? am i on the right track? Thanks!