Hi, I m trying to find out, what is imaginary unit/number. i^2

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The discussion revolves around the concept of imaginary numbers, particularly the imaginary unit "i," which is defined as the square root of -1. Participants explore the historical context and mathematical necessity for introducing imaginary numbers, highlighting their role in solving polynomials and providing real solutions to otherwise unsolvable problems. The conversation also touches on the philosophical implications of defining numbers and mathematical operations, suggesting that mathematicians create frameworks that extend beyond traditional real numbers. A geometric interpretation is presented, where "i" is visualized as a 90-degree rotation in a two-dimensional plane, illustrating how complex numbers can be understood as points in this plane. Ultimately, the dialogue emphasizes the consistency and utility of these mathematical constructs in broader mathematical applications.
  • #31


PlanckShift said:
1/ε is undefined. It is so a field. It's closed under linear combinations. It's commutative and associative. It has an identity element: 1+ε0 and the inverse element which I've described already. It's distributive, too.

The nonzero elements of a field are an abelian group under multiplication, so \epsilon^{-1} = \frac{1}{\epsilon} must exist if \epsilon \ne 0.
 
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  • #32


The real numbers are a field even though 0-1 doesn't exist. It's the same thing with this definition of complex numbers although elements along the "imaginary" line don't have inverses.
 
  • #33


PlanckShift said:
The real numbers are a field even though 0-1 doesn't exist. It's the same thing with this definition of complex numbers although elements along the "imaginary" line don't have inverses.

Please stop spouting nonsense and review basic mathematics.
Nonzero imaginary numbers do have inverses: i^{-1}=-i.
 
  • #34


micromass said:
Please review your definition of a field.

Definition of a field.
 
  • #35


PlanckShift said:
Definition of a field.

OK, you found the definition. Now read the definition. In particular:

Similarly, for any a in F other than 0, there exists an element a−1 in F, such that a · a−1 = 1.
 
  • #36


But ε2 = 0 remember? Think about it. How do you find the inverse of a+bε? Rationalize the expression using ε2 = 0. Then find where the resulting expression is undefined.
 
  • #37


PlanckShift said:
But ε2 = 0 remember? Think about it. How do you find the inverse of a+bε? Rationalize the expression using ε2 = 0. Then find where the resulting expression is undefined.

But where is the inverse of ε?
Hint: It's 1/ε, which you said was undefined. It doesn't have an inverse, so your structure isn't a field.
 

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