Hi. Say we want to parametrize the plane R^2.

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SUMMARY

The discussion focuses on parametrizing the plane R² using different coordinate systems. It establishes that (x,y) Cartesian coordinates and (r,θ) polar coordinates are valid parametrizations, while (x,r) coordinates are not due to their potential to map to multiple points. A valid parametrization requires a single-valued function from the parameter space (u,v) onto the (x,y) plane. The failure of the (x,r) parametrization is exemplified by the mapping of (1,2) to two distinct points: (1,sqrt(3)) and (1,-sqrt(3)).

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  • Basic concepts of parametrization in geometry
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Mathematicians, students of calculus, and anyone interested in geometric parametrization techniques will benefit from this discussion.

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Hi. Say we want to parametrize the plane R^2. This can be done for example using (x,y) cartesian, i.e. a pair of intersecting lines, OR (r,theta) polar coordinates, i.e. a half line intersecting a circle. But it cannot be done using (x,r) coordinates, i.e. a line intersecting a circle, because sometimes the line will not intersect the circle, sometimes it will intersect it once and sometimes it will intersect the circle twice! How can I know whether a parametrization is any good? I.e. on what mathematical grounds can I reject the (x,r) parametrization?
 
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daudaudaudau said:
Hi. Say we want to parametrize the plane R^2. This can be done for example using (x,y) cartesian, i.e. a pair of intersecting lines, OR (r,theta) polar coordinates, i.e. a half line intersecting a circle. But it cannot be done using (x,r) coordinates, i.e. a line intersecting a circle, because sometimes the line will not intersect the circle, sometimes it will intersect it once and sometimes it will intersect the circle twice! How can I know whether a parametrization is any good? I.e. on what mathematical grounds can I reject the (x,r) parametrization?

You at least need a function from your parameter space (u,v) onto the (x,y) plane. And a function must be single valued. Your example fails because the (x,r) = (1,2) would map to two points: (1,sqrt(3)) and (1,-sqrt(3)).
 

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