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Eli137
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As you may know, the mass of the Higgs Boson is 125 GeV. My question is, "How can the particles themselves that create mass by interacting with others have mass?"
If the Higgs Bosons are just the product of an energy field, are they really necessary for the interactions with particles that gives them mass?Nugatory said:
Eli137 said:If the Higgs Bosons are just the product of an energy field, are they really necessary for the interactions with particles that gives them mass?
Because of that, my question is: What do Higgs bosons do if they aren't the reason particles have mass?Drakkith said:What do you mean by 'are they really necessary'? You certainly don't need to have Higgs Bosons lying about everywhere just so particles have mass, the Higgs field does this by itself.
Thank youOrodruin said:The Higgs bosons are a necessary consequence of the Higgs mechanism. If the Higgs field exists, so do the Higgs bosons. The Higgs field must exist if it is to take a non zero vacuum expectation value, which is what gives other particles their mass and therefore the Higgs boson must exist because it does if the field does. (You may think of the field as the surface of a pond and the particle as ripples on the surface - if the surface is there, you can make ripples.)
Since the Higgs boson and particle masses are both predictions of the same theory, we can deduce some of the properties the Higgs boson must have (such as its interactions) from knowledge of particle masses.
mfb said:It doesn't fit in that framework of two or three "forces". You can consider its interactions as a separate "force" if you like.
vanhees71 said:Now a space reflection is defined by the substitution t→tt \rightarrow t, r⃗ →−r⃗ \vec{r} \rightarrow -\vec{r}. Since p⃗ =mdx⃗ /dt⃗ \vec{p}=m \mathrm{d} \vec{x}/\mathrm{d} \vec{t} and since we assume that m→mm \rightarrow m under space reflections also p⃗ →−p⃗ \vec{p} \rightarrow -\vec{p}, but L⃗ ⇒(−r⃗ )×(−p⃗ )=r⃗ ×p⃗ =L⃗ \vec{L} \Rightarrow (-\vec{r}) \times (-\vec{p})=\vec{r} \times \vec{p}=\vec{L}. So L⃗ \vec{L} doesn't flip its sign under space reflections. This is what's called an axial vector.
Yes, if you have a usual right-handed skrew and you look at it in a mirror, it looks left-handed. So everything that has some sense of winding flips the relative orientation of the corresponding direction and the associated rotation.Drakkith said:Interesting. It's like the right-hand rule for angular momentum becomes a left-hand rule in a reflection. Is that right?
vanhees71 said:One should note, however that a mirror flips only one component of axial directions. If the mirror is in the xy plane all polar vectors undergo the transformation (x,y,z)→(x,y,−z)
vanhees71 said:Usually the space reflection is a reflection at a point (usually the origin of your coordinate system). So the mirror reflection is a space reflections followed by a rotation by an angle π around the normal direction of the mirror.
The "B" tag in the thread title means beginner level (i.e., the OP is at high-school level or below). The OP is likely not even familiar with the cross product. The BIA tags were introduced specifically for people to be able to gauge the level of answer required for the OP.vanhees71 said:Who knows? I hope, he or she will ask further questions if not!
vanhees71 said:Who knows? I hope, he or she will ask further questions if not!
Just to say that this was the entire idea behind the introduction of the BIA tags. For people who are not interested in replying to B level threads to know that they can save the time it would take to open the thread, for people who are at B level not having to open A level threads, and for responders who are happy responding to all levels to understand the appropriate level of response which may be understood by the OP.vanhees71 said:Well, I had not the impression that with the other answers the question was even addressed. If this is what a "B" tag mandatorily means, I'd rather not post to B-tagged questions anymore!
vanhees71 said:Very complicated, and I thought that this posting is ok for a high-school student. Sorry for that. I'll refrain from answering to B threads (to be honest, however, I don't look too much at these tags; so if I should answer a B-thread in the future, I apologize in advance).
Hi Vanhees:vanhees71 said:It's difficult to answer this question, because it involves pretty advanced math to understand, why the Higgs mechanism (as a theoretical concept) is necessary to give the particles mass. The reason is that the mass of particles is doubly "problematic" in the quantum-field theoretical model that describe electroweak interaction.
Buzz Bloom said:Fields are continuous and particles are discrete. A particle is the quantized equivalent of it's field. Fields interact with fields, and particles interact with fields, but particles do not directly interact with particles. When a particle interacts with a field, or a field interacts with a field, some quantities are exchanged, for example: charge, spin, energy, and momentum. Charge and spin are of course quantized, but energy and momentum in classical physics are continuous. However, for quantum fields, the specific values of energy and momentum exchanged are limited to a set of discrete values.
nikkkom said:Particles are excitations of fields.
There is a very, very good explanation of all this with a very small amount of math
nikkkom said:Particles are excitations of fields.
There is a very, very good explanation of all this with a very small amount of math:
http://profmattstrassler.com/articl...-basics/fields-and-their-particles-with-math/
The Higgs Boson is a subatomic particle that was first theorized in the 1960s by physicist Peter Higgs. It is a fundamental particle that is believed to give other particles their mass through the Higgs Field.
The mass of the Higgs Boson was determined through experiments at the Large Hadron Collider (LHC) at CERN. Scientists used data from particle collisions to calculate the mass of the Higgs Boson to be approximately 125 GeV (gigaelectronvolts).
The mass of the Higgs Boson at 125 GeV was a major discovery in the field of particle physics. It confirmed the existence of the Higgs Field and provided evidence for the Standard Model of particle physics. It also helped to explain how particles acquire mass, a fundamental property in the universe.
The Higgs Field is an invisible field that permeates the entire universe. When particles interact with this field, they are slowed down and acquire mass. The more a particle interacts with the Higgs Field, the more massive it becomes.
The discovery of the Higgs Boson has opened up new avenues for research in particle physics. It has provided a deeper understanding of the fundamental building blocks of the universe and has potential applications in fields such as cosmology and quantum mechanics. Scientists continue to study the properties of the Higgs Boson and its interactions with other particles to further our understanding of the universe.