B Higher Dimensional Vectors

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Hornbein
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The 26 dimensional space of bosonic string theory could be denoted with alphabetical vectors.
[a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z,].

The 196,883 dimensions of the monster group could be represented with all possible sequences of the first 21 letters plus all possible sequences of the last seven letters, plus one more symbol, presumably "a".

So [a, aaaaaaaaaaaaaaaaaaaaa, aaaaaaaaaaaaaaaaaaaab, aaaaaaaaaaaaaaaaaaaac ... vvvvvvvvvvvvvvvvvvvvv, ttttttt, ttttttu, .... zzzzzzz ]
 
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Isn't it better to simply use subscripts for these types of vectors?
 
A bit of a pedantic comment, but 196 883 is not the dimension of the group. It is the dimension of the minimal faithful representation (over the complex numbers).
 
What's the point of this thread?
 
What's the point of anything?
 
Thread 'Determine whether ##125## is a unit in ##\mathbb{Z_471}##'
This is the question, I understand the concept, in ##\mathbb{Z_n}## an element is a is a unit if and only if gcd( a,n) =1. My understanding of backwards substitution, ... i have using Euclidean algorithm, ##471 = 3⋅121 + 108## ##121 = 1⋅108 + 13## ##108 =8⋅13+4## ##13=3⋅4+1## ##4=4⋅1+0## using back-substitution, ##1=13-3⋅4## ##=(121-1⋅108)-3(108-8⋅13)## ... ##= 121-(471-3⋅121)-3⋅471+9⋅121+24⋅121-24(471-3⋅121## ##=121-471+3⋅121-3⋅471+9⋅121+24⋅121-24⋅471+72⋅121##...
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