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hemetite
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Homework Statement
What is the highest harmonic of this string that is within the typical human's audible range (up to 20000 Hz)
String length of 16m
u = liner density = 0.015 g/cm = 0.0015 kg/m
stretched tension of the string = 557N
Homework Equations
v= sqrt ( F/ u)
v= lamba * frequency
lamba = 2 Length / n
The Attempt at a Solution
v= sqrt ( F/ u) = sqrt ( 557/0.0015 ) = 609.37
up to human's typical audible frequency = 20000 Hz
v= lamba * frequency
609.37 = lamba * 20 000 Hz
lamba = 0.0304685
therefore lamba = 2 length /n
0.0304685 = (2* 16) / n
n=1050.265
Ans: the highest harmonic of the string that is within human's audible range = 1050 harmonics.
Am i right?...