Calculating Torque and Rotational Kinetic Energy: Homework Help

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The discussion focuses on two physics problems involving torque and rotational kinetic energy. For the first problem, participants confirm the calculations for torque produced by forces of 4 N and 9 N, which yield 1.2 N*m counterclockwise and 2.7 N*m clockwise, respectively. To solve for torque when the force is not perpendicular, it is suggested to use the component of the force that is perpendicular to the radius. In the second problem, the moment of inertia is correctly calculated as 0.96 kg*m^2, and the formula for rotational kinetic energy is provided as 1/2 I ω^2, where ω is the angular speed in radians per second. Overall, the thread provides guidance on solving torque and rotational kinetic energy problems in physics.
vitaly
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I need some help with these two problems:

1. A wheel of radius 30 cm has forces applied to it as shown in the figure below. Find the torque produced by the force of (a) 4 N (b) 9 N (c) 7 N (d) 6 N. See attachment for figure.
(a) = _____1.2 N*m_____ counterclockwise?
(b) = _____2.7 N*m_____ clockwise?
(c) = __________ N*m
(d) = __________ N*m clockwise
For a, I did: (4N)(.3 M ) = 1.2 N*m
for b, (9 N)(.3 M) = 2.7 N*m
for c, I don't know how to solve it if hte force isn't perpendicular.
for d, same as c. Does anybody know how to solve for c and d, and does anybody know if a and b are correct?

2. A wheel, of mass 6 Kg and radius of gyration 40 cm, is rotating at 300 rpm. Find its momentum of inertia and its rotational KE.
I got:
I = mr^2 = (6 Kg)(0.4 m)^2 = 0.96 kg*m^2. Is that right?
And I'm not sure how to find the rotational kinetic energy. Is there an equation I need?

All help is appreciated. thank you
 

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For the second,what is the moment of inertia of a disk...?

Daniel.
 
ke

rotational KE is given by 1/2* I * (w^2)
where I is moment of inertia and w is the angular velocity...
wiz
 
Radius of Gyration does not equal the radius of the disk. You will have to find an equation relating mass, Moment of Intertia, and Radius of Gyration. Hint: It involves a division sign and a square root. From there, it is easy to find your Moment of Interia.

To find the rotational interia, it is basically the same equation for linear, but with circular definitions in. (i.e. rad/s instead of m/s, angular velocity instead of linear velocity)
 
vitaly said:
1. A wheel of radius 30 cm has forces applied to it as shown in the figure below. Find the torque produced by the force of (a) 4 N (b) 9 N (c) 7 N (d) 6 N. See attachment for figure.
(a) = _____1.2 N*m_____ counterclockwise?
(b) = _____2.7 N*m_____ clockwise?
(c) = __________ N*m
(d) = __________ N*m clockwise
For a, I did: (4N)(.3 M ) = 1.2 N*m
for b, (9 N)(.3 M) = 2.7 N*m
Good.
for c, I don't know how to solve it if hte force isn't perpendicular.
for d, same as c. Does anybody know how to solve for c and d, and does anybody know if a and b are correct?
When the force is not perpendicular to the radius, find the component of the force perpendicular to the radius. (Hint: F sin\theta, where \theta is the angle that the force makes with the radius.)

a and b are correct.


2. A wheel, of mass 6 Kg and radius of gyration 40 cm, is rotating at 300 rpm. Find its momentum of inertia and its rotational KE.
I got:
I = mr^2 = (6 Kg)(0.4 m)^2 = 0.96 kg*m^2. Is that right?
This is correct.
And I'm not sure how to find the rotational kinetic energy. Is there an equation I need?
{KE}_{rot} = 1/2 I \omega^2
where \omega is the angular speed (measured in radians/sec).
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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