Homework SolutionQuantum Operators: Pr Y & Pr^2 Y

[Chronos000]

Homework Statement

I'm given the expression for the operator Pr Y

Pr Y= -ih(bar) (1/r) d/dr (r Y)

I want to find Pr^2 Y so I have dotted Pr with Pr

I expect to get:

-h(bar)^2 (1/r) d/dr [ Y(Y + r dY/dr)]

but my notes have omitted the first Y in the above bracket and I can't see why.

 

[Oerg]

there's nothing wrong with the answer, the Y shouldn't be there. Pr^2 Y means operating Pr on Pr Y

 

[Chronos000]

so it is! thanks