Homework SolutionQuantum Operators: Pr Y & Pr^2 Y

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SUMMARY

The discussion centers on the quantum mechanical operator Pr and its application to the function Y. The operator Pr is defined as Pr Y = -ih(bar) (1/r) d/dr (r Y). The user seeks to compute Pr^2 Y by applying the operator Pr twice, leading to the expression -h(bar)^2 (1/r) d/dr [Y(Y + r dY/dr)]. However, the user notes that their notes omit the first Y in the expression, which is confirmed to be unnecessary. The conclusion is that Pr^2 Y correctly represents the operation of Pr on Pr Y without the additional Y term.

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Chronos000
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Homework Statement



I'm given the expression for the operator Pr Y

Pr Y= -ih(bar) (1/r) d/dr (r Y)

I want to find Pr^2 Y so I have dotted Pr with Pr

I expect to get:

-h(bar)^2 (1/r) d/dr [ Y(Y + r dY/dr)]

but my notes have omitted the first Y in the above bracket and I can't see why.
 
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there's nothing wrong with the answer, the Y shouldn't be there. Pr^2 Y means operating Pr on Pr Y
 
so it is! thanks
 

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