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Homology of the Klein Bottle using M-V sequences

  1. Mar 10, 2009 #1

    quasar987

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  3. Mar 10, 2009 #2

    matt grime

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    The homology group is Z + Z quotiented by the image of alpha. In the given bases label them e,f, what is this? It is <e,f>/(2f=0) i.e. Z + Z/2Z
     
  4. Mar 10, 2009 #3
    How do you compute the quotient

    [tex]\frac{\ker(d_n)}{\text{im}(d_{n+1})}[/tex]

    ? If you can express [tex]\ker(d_n)[/tex] and [tex]\text{im}(d_{n+1})[/tex] in terms of the same basis, then modding out is straight forward. That's why Wiki is choosing a non-standard basis for Z². Why don't you write out the sequence and the maps?
     
    Last edited: Mar 10, 2009
  5. Mar 11, 2009 #4

    quasar987

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    Thanks. I had forgotten that given a short exact sequence 0-->A-f->B-->C-->0, we have C=B/Im(f).

    Actually, there is no need to talk about basis here since Im(alpha) is clearly just 2Z, so H_1(K)=(Z+Z)(2Z)=Z+Z/2Z.
     
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